The brown ring complex compound is formulated as [Fe (H2O) 5 NO]SO4. The oxidation state of iron is (1) +1 (2) +2 (3) +3 (4) +6

Answer: (1)

In the above compound the oxidation number of iron can be determined as follows:

[Fe(NO)(H2O)5]SO4 dissociate in water to give [Fe(NO)(H2O)5]2+ ions and SO42- ions.

Charge on NO = +1 ( NO+)

H2O = Neutral ligands

The oxidation state of iron (Fe)

⇒ X + (+1) + 5(0) = +2

⇒ X = +1

1 Comment

  1. sanjaymohanpagadal

    Helpful

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