The diameter of a brass rod is 4mm and Youngs modulus of brass is 9 x 10^10 N/m^2. The force required to stretch it by 0.1% of its length is (A) 360πN (B) 36 N (C) 144π x 10^3N (D) 36π x 10^5N

Let F = Force

Y = Young’s modulus

Δ = change in length

l = length

F = (YAΔl)/l

Given Δl/l = 0.001

Y = 9 x 1010 N/m2

r = 2mm

A = πr2 = π x (2 x 10-3)2 m2

F = (YAΔl)/l

= 9 x 1010 x π x 4 x 10-6 x 0.001

We get,

= 360πN

Therefore, the correct option is (A)

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