The dimensional formula for permittivity of free space (?0) in the equation F = (1/4??0) (q1q2/r2) where, symbols have their usual meaning is (1)

Answer:

The permittivity of free space

\(\varepsilon _{0} = \frac{q_{1}q_{2}}{4pi Fr^{2}}\)

Dimensions of F = [MLT-2]

Dimensions of q = [AT]

Dimensions of r = [L] \(Dimension of \varepsilon _{0} = \frac{\left [ AT \right ]\left [ AT \right ]}{\left [ MLT^{-2} \right ]\left [ L^{2} \right ]}\) \(\varepsilon _{0} = \left [ M^{-1}L^{-3}T^{^{4}} A^{2}\right ]\)

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