The electric potential at a point in free space due to charge Q coulomb is Q x 10^11V. The electric field at that point is

Here,

[latex]V = \frac{1}{4\pi \epsilon _{0}}.\frac{Q}{r}=Q.10^{11}volts[/latex]

Hence,

[latex]\frac{1}{r}=4\pi \epsilon _{0}.10^{11}[/latex]

E = potential / r

[latex]E = Q.10^{11}\times 4\pi \epsilon _{0}.10^{11}[/latex]

Therefore,

[latex]E = 4\pi \epsilon _{0}Q.10^{22}volt/m[/latex]

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