The electric potential at a point in free space due to charge Q coulomb is Q x 10^11V. The electric field at that point is

Here,

$V = \frac{1}{4\pi \epsilon _{0}}.\frac{Q}{r}=Q.10^{11}volts$

Hence,

$\frac{1}{r}=4\pi \epsilon _{0}.10^{11}$

E = potential / r

$E = Q.10^{11}\times 4\pi \epsilon _{0}.10^{11}$

Therefore,

$E = 4\pi \epsilon _{0}Q.10^{22}volt/m$

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