Question

The electronic configuration of ${\mathrm{Eu}}^{3+}$ion is:

Answer 1

Electronic configuration

• The distribution of electrons into orbitals of an atom is called its electronic configuration.

Electronic configuration of ${\mathrm{Eu}}^{3+}$ion

• The symbol for Europium is $\mathrm{Eu}$ and has an atomic number $63$.
• The electronic configuration of $\mathrm{Eu}\mathrm{is}$ $\left[\mathrm{Xe}\right]4{\mathrm{f}}^{7}6{\mathrm{s}}^2$.
• It is an f-block element and comes under the lanthanide series.
• The common oxidation state shown by lanthanides is $+3$ so when $\mathrm{Eu}$ loses $3$electrons, it becomes ${\mathrm{Eu}}^{3+}$ ion.
• So, the electronic configuration of ${\mathrm{Eu}}^{3+}$ion is $\left[\mathrm{Xe}\right]\mathbf{4}{\mathbf{f}}^{\mathbf{6}}$.