The equivalent weight of K2Cr2O7 in acidic medium is expressed in terms of its molecular weight (M) as (1) M/3 (2) M/4 (3) M/6 (4) M/7

Answer: (3)

The equivalent weight of K2Cr2O7 = 49 g/mol

In the solution, K2Cr2O7 gives the following ions,

K2Cr2O7 + 14H+ + 6e→ 2K+ + 2Cr3+ + 7H2O

The chemical equivalent is 6 because six electrons participate in the chemical reaction.

Formula to calculate equivalent weight is

Equivalent weight (Z) = molecular weight / chemical equivalent

Z = M/6

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