The Equivalent Weight Of K2CrO4, When It Reacts With AgNO3 To Give Ag2CrO4 Is _______. (A) M. (B) M/2. (C) M/3. (D) Infinite.

The correct answer is (B) M/2.

As given in the question:

K2CrO4 reacts with AgNO3 to give Ag2CrO4.

K2CrO + AgNO3 → Ag2CrO4 + KNO3

The Equivalent Weight = \( \frac{Molecular Weight}{Valency}\)

Valency = Valency of cation = 2

Let M be the molecular weight of K2CrO4.

Therefore, the equivalent weight of K2CrO= \(\frac{M}{2}\)

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