Question

The interaction between earth and moon which keeps the moon revolving around the earth can be named as a ?

Answer 1

The interaction between earth and moon which keeps the moon revolving around the earth:

1. The gravitational force exerted by the earth on the moon provides the necessary centripetal force required for the moon to orbit the earth.
2. From Earth, it might look like the moon is stationary, and is not moving, but in reality, each year the moon gets 3 cm away from Earth.
3. Without having the force of Gravity from the earth-moon would have just floated away from us.
4. The moon's velocity and distance from Earth allow it to make a perfect balance between fall and escape.
5. The interaction between earth and moon, which keeps the moon revolving around the earth, is basically happening due to the existence of the force of gravity between them which is simply a kind of force depending upon its nature.
6. The gravitational force exerted by the earth on the moon can be given by Newton's equation:

${\mathrm{F}}_{\mathrm{g}}=\mathrm{G}\frac{{\mathrm{m}}_{}{\mathrm{m}}_E}{{\mathrm{r}}^2}$

Where,${\mathrm{F}}_{\mathrm{g}}=$Gravitational force

G = universal gravitational constant, usually referred to as “big G”

${\mathrm{m}}_1\mathrm{and}{\mathrm{m}}_2$ = the masses of the moon and earth, respectively.

$\mathrm{r}=$the radius of revolution

Here the gravitational force also accounts for the centripetal force of attraction, which can be given as:

${\mathrm{F}}_{\mathrm{c}}=\mathrm{G}\frac{{\mathrm{m}}_{}{\mathrm{m}}_E}{{\mathrm{r}}^2}=\frac{{\mathrm{mv}}^2}{\mathrm{r}}$

Where ${\mathrm{F}}_{\mathrm{c}}=$the centripetal force,

$\mathrm{v}=$the velocity of revolution, which is given by:

$\mathrm{v}=\sqrt{\frac{{\mathrm{Gm}}_E}{{\mathrm{r}}^{}}}$

Hence, the interaction between the earth and the moon, which keeps the moon revolving around the earth, can be named as the force of gravity.