Question

The magnetic field in a traveling electromagnetic wave has a peak value of $20nT.$ What is the peak value of electric field strength?

Answer 1

Step 1; Given data.

The peak value of the magnetic field in the electromagnetic wave is $\left(B_0\right)=20nT=20\times {10}^{-9}T$

Assume that the peak value of the electric field is $E_0$

Step 2: Finding the peak value of the electric field.

The relation between $E_0$ and $B_0$ is

$E_0=c{B}_0$

where $E_0$ is the electric field

$B_0$ is the magnetic field

$c$ is the velocity of light in free space.

Substituting the values in the above equation,

$$\begin{gathered} E_0=3\times {10}^8\times 20\times {10}^{-9} \\ {E}_0=6V/m \end{gathered}$$

Hence, the peak value of the electric field is $6V/m$