The mass of oxalic acid crystals required to prepare 50 mL of a 0.2 N solution is:

Given

Oxalic acid and 50mL of 0.2 N solution

Find out

We need to find out the mass of oxalic acid crystals required to prepare 50 mL of a 0.2 N solution

Solution

Oxalic acid exists as the dihydrate CHO.2HO.

Molecular weight of oxalic acid dihydrate = 126 g / mol

Gram equivalent weight = Molecular weight / basicity

= 126/2

= 63 g / mol

1 Normal solution of oxalic acid should have 63 g in 1 L.

0.2 Normal solution of oxalic acid should have

= 12.6 g in 1 L.

0.2 Normal solution of oxalic acid should have in 50 mL.

= 0.63 g in 50 mL.

Answer

The mass of oxalic acid crystals required to prepare 50 mL of a 0.2 N solution = 0.63g

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