The no of the tetrahedral void is always 8 for any fcc lattice? As the Zeff of Fcc is 4 which is unchanged always.

If in a close-packed structure (ccp or fcc) there are no atoms or ions then the number of octahedral voids and tetrahedral voids will be nn and 2n2n respectively. there are 8 tetrahedral voids per unit cell of fcc structure Zeff = 4. If you divide the FCC unit cell into 8 small cubes then each small cube has 1 tetrahedral void located at its own body center. Thus, the total number of TVs in a unit cell = 8= 2*Zeff

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