a) 2.5 x 103 A/m
b) 2.5 x 105 A/m
c) 2.0 x 103 A/m
d) 2.0 x 103 A/m
Answer: b) 2.5 x 105 A/m
Solution:
Here, n = 500 turns/m
I = 1 A
μr = 500
Magnetic intensity, H = nI = 500 x 1= 500 A/m
μr = 1 + χ
Where χ is the magnetic susceptibility of the material
χ = μr – 1
Magnetisation M =χH
= (μr – 1)H
= (500 – 1) x 500
= 499 x 500
= 2.495 x 105 A/m
= 2.5 x 105 A/m