Three identical particles are joined together by a thread as shown in figure .All the 3 particles are moving in a horizontal plane .if the velocity of the outermost particle isV ,then the ratio of tension in the three section of the string (a)3:5:7 (b) 3:4:5 (c)7:11:6 (d) 3:5:6

Solution

As per the given data angular velocity ω is same for all

Tc=mω2(3ℓ)

TB=Tc+mω2(2ℓ)= mω2(5ℓ)

TA=TB+mω2(ℓ)= mω2(6ℓ)

∴Tc:TB:TA::3:5:6

Answer

The ratio of tensions in the three sections of the string is 3:5:6

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