# To What Temperature Must A Neon Gas Sample Be Heated To Double Its Pressure If The Initial Volume Of Gas At 75°c Is Decreased By 15.0% By Cooling The Gas?

Given :

Initial temperature is T1 = 75°C

Initial volume is V1

Initial pressure is P1

The final temperature is T2 = 273 + 75 = 348 K

$$V_{2} = V_{1} – \frac{15}{100}V_{1} \\\Rightarrow \frac{85\; V_{1}}{100}$$

Now by applying the gas formula,

$$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}} \\\Rightarrow \frac{P_{1}V_{1}}{348} = \frac{2\;P_{1}85\;V_{1}}{T_{2}} * 100\\\Rightarrow T_{2} = \frac{2\; * \;85 \;* \;348}{100} \\\Rightarrow T_{2} =591.6 K$$

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