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Question

Two boys are standing at the ends A and B of a ground, where AB=a. The boy at B starts running in a direction perpendicular to AB with velocity v1​. The boy at A starts running simultaneously with velocity v and catches the other boy in a time t, where t is


A

av2-v12

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B

aV+V1

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C

aV-V1

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D

av2+v12

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Solution

The correct option is A

av2-v12


Step 1: Given data

d=a

Step 2: Calculate time

From the above diagram.

vt2=a2+v1t2........(Usingpythagorastheorem)v2t2-v12t2=a2t=av2-v12

Here, v is the resultant velocity,v1 is perpendicular velocity , a is distance and t is time.

Hence, option(A) is correct.


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