In series current is same$$i_{x } = i_{y}$$

For the same diameter, the cross-sectional area will be the same.

Therefore,

$$n_{x} eAv_{x} = n_{y}eAv_{y}$$

=$$\frac{v_{x}}{v_{y}}$$

=$$\frac{n_{y}}{2n_{y}}$$

=$$\frac{1}{2}$$

Therefore,$$v_{x} : v_{y} = 1:2$$

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