# Two positively charged particles, each of mass 1.7 x 10−27 kg and carrying a charge of 1.6 x10−19 C are placed at a distance d apart. If each experiences a repulsive force equal to its weight, find the value of d.

Given:

m = $1.7 * 10^{-27}$ kg

q = $1.6 * 10^{-19}$ C

$F_{electrostatic} = F_{gravity}$

As we know: $\frac{kq^{2}}{d^{2}}$= mg

$\Rightarrow \frac{9 * 10^{9}(1.6 * 10^{-19})^{2}}{d^{2}}$ $\Rightarrow 1.7 * 10^{-27} * 10$ $\Rightarrow$d = 0.11 m = 11 cm.

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