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Question

What is the lowest total resistance that can be secured by combinations of four coils of resistance 4Ω,8Ω,12Ω,24Ω?


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Solution

Step 1: Given information

Combinations of four coils of resistance are:

R1=4Ω

R2=8Ω

R3=12Ω

R4=24Ω

Step 2: Calculation

If these coils are connected in parallel, the equivalent resistance, given by, will be the lowest. Net resistance is given by

1Rnet=14Ω+18Ω+112Ω+124Ω1Rnet=6+3+2+124Ω1Rnet=1224Ω1Rnet=12ΩRnet=2Ω

Hence, the lowest resistance is 2Ω.


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