I = integral of log([1/x] – 1) dx ——- (1)
I = integral of log(1/1-x – 1) dx
I = Integral 0 to 1 log(1-[1-x]/[1-x]) dx
I = Integral 0 to 1 log(x / 1-x) dx ——- (2)
Add (1) and (2)
2I = 0
I = 0
I = integral of log([1/x] – 1) dx ——- (1)
I = integral of log(1/1-x – 1) dx
I = Integral 0 to 1 log(1-[1-x]/[1-x]) dx
I = Integral 0 to 1 log(x / 1-x) dx ——- (2)
Add (1) and (2)
2I = 0
I = 0
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