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Question

What is the oxidation state of each individual carbon atom in C2O42-?


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Solution

Step 1: Oxidation state:

  • "Oxidation state of an element in a compound ascertained according to a set of rules formulated on the basis that electron pair in a covalent bond belongs entirely to a more electronegative element."

Step 2: Calculation for oxidation state in C2O42-:

  • The overall charge on C2O42-is -2.
  • Let "x" be the oxidation state of the Carbon atom:
  • The oxidation state of Oxygen is -2.

2×x+(4×-2)=-22x-8=-22x=-2+82x=+6x=62x=+3

Thus, the Oxidation state of each Carbon atom in C2O42- is +3.


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