# What Is The Percentage Strength (Weight/Volume) Of 11.2 V H2O2?

One mL of $$H_{2}O_{2} = \frac{68\;x}{22400}\;g \;H_{2}O_{2}$$.

Here, x is the volume strength of

$$H_{2}O_{2}$$, which is equal to 11.2L.

Therefore, One mL of

$$H_{2}O_{2} = \frac{68\;x\; * 11.2}{22400}g \\\Rightarrow 0.034g of H_{2}O_{2}$$

The percentage strength of
$$H_{2}O_{2} = 0.034g * 100 \\\Rightarrow 3.4 % (w / v).$$

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