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Question

What is the shape of SF4 (including bond angles)?


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Solution

Hybridization:

  • It is the process of intermixing of the orbitals of slightly different energies so as to redistribute their energies, resulting in the formation of a new set of orbitals of equivalent energies and shapes.
  • The hybridized orbitals are always equivalent in energy and shape.

The formula used to calculate the hybridization of a molecule is as follows:

  • Numberofelectronpair=12[V+N-C+A]

where,

V is the number of valence electrons present in the central atom

N is the number of monovalent atoms bonded to the central atom

C is the charge of cation

A is the charge of anion

  • The given molecule is, SF4

Numberofelectronpair=12[6+4-0+0]=102=5

  • The number of electron pairs is 5 which means the hybridization will be sp3d and the electronic geometry of the molecule will be trigonal bipyramidal.
  • But as there are 4 atoms around the central sulphur atom, the 5th position will be occupied by lone pair of electrons.
  • Hence the molecular geometry will be a see-saw.

Therefore, the shape of SF4 is see-saw and bond angle is 90oand120o.


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