When An Alpha Particle Of Mass M Moving With Velocity V Bombards On A Heavy Nucleus Of Charge Ze Its Distance Of Closest Approach From The Nucleus Depends On M As:

The particle’s kinetic energy will convert completely into electrostatic potential energy at the closest distance of approach.

\( \Rightarrow \frac{1}{2}mv^{2} \) \( \Rightarrow \frac{KQq}{d} \) \( \Rightarrow d \propto \frac{1}{m} \)

Explore more such questions and answers at BYJU’S.

Was this answer helpful?

 
   

0 (0)

(0)
(0)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question