# When An Alpha Particle Of Mass M Moving With Velocity V Bombards On A Heavy Nucleus Of Charge Ze Its Distance Of Closest Approach From The Nucleus Depends On M As:

The particle’s kinetic energy will convert completely into electrostatic potential energy at the closest distance of approach.

$$\Rightarrow \frac{1}{2}mv^{2}$$ $$\Rightarrow \frac{KQq}{d}$$ $$\Rightarrow d \propto \frac{1}{m}$$

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