When The Velocity Of A Relativistic Charged Particle Increases Its Specific Charge ______.

When the velocity of a relativistic charged particle increases, its specific charge decreases.

\(m = \frac{m0}{\sqrt{1-\frac{v^{2}}{c^{2}}}}\)

specific charge \(\frac{q}{m} = \frac{q}{m0}\sqrt{1 – \frac{v^{2}}{c^{2}}}\)

Therefore, as the velocity of a relativistic charged particle increases, the specific charge decreases.

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