Why Barium Nitrate does not give Brown ring test?

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Solution

Brown Ring Test:
A chemical test known as a nitrate test is performed to identify the presence of nitrate ion in any solution.
Since almost all nitrates dissolve in water, detecting the presence of nitrate using wet chemistry is more difficult than testing for other anions.
Numerous tests for the nitrate anion rely on the fact that it is an oxidizer.
The presence of additional oxidants in the analyte may interfere and cause inaccurate findings.
Barium Nitrate:
Barium Nitrate reacts with ${FeSO}_{4}$ to form Barium Sulphate ${BaSO}_{4}$ which prevents the formation of brown ring.
That is why Barium Nitrate does not show a brown ring test.
The reaction is as follows:-
${FeSO}_{4} (s) + Ba {({NO}_{3})}_{2} (s) \to {BaSO}_{4} (s) + Fe {({NO}_{3})}_{2} (s)$

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Similar questions

(a) Explain with the help of a balanced equation, the brown ring test for nitric acid.

(b) Why is freshly pepared ferrous sulphate solution used for testing the nitrate radical in the brown ring test ?

Choose the correct answer :

(a) The nitrate salt which does not give a mixture of $N O_{2}$ and $O_{2}$ on heating is :

(i) $A g N O_{3}$ , (ii) $K N O_{3}$ ,

(iii) $C u (N O_{3})_{3}$ , (iv) $Z n (N O_{3})_{2}$ .

(b) The chemical used in the brown ring test is :

(i) $C u S O_{4}$ , (ii) $F e S O_{4}$

(iii) $F e_{2} (S O_{4})_{3}$ (iv) $Z n S O_{4}$ .

(i) NO, (ii) $N_{2} O,$

(iii) $N O_{2}$ (iv) $N_{2} O_{5}$ .

A brown ring is formed in the ring test for ${NO}_{3}^{-}$ ,i.e. nitrate ion. Why the brown ring is formed?

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