Write the Distribution of Electrons in Carbon and Sodium Atom?

Answer:

Carbon

The atomic number of carbon is 6. The electronic configuration of carbon is

C(Z = 6) = 1s² 2s² 2p²

The distribution of electrons in the carbon atom is as follows:

• In the first orbit or K-shell = 2 electrons
• In the second orbit or L-shell = 4 electrons

Or, we can write the distribution of electrons in a carbon atom as 2, 4.

Sodium

The atomic number of sodium is 11 and the electronic configuration of sodium is,

Na(Z = 11) = 1s² 2s² 2p⁶ 3s¹

The distribution of electrons in the sodium atom is as follows:

• In the first orbit or K-shell = 2 electrons
• In the second orbit or L-shell = 8 electrons
• In the third orbit or M-shell = 1 electron

Or, we can write the distribution of electrons in a sodium atom as 2, 8, 1.