RD Sharma Solutions for Class 7 Maths Chapter 13 – Simple Interest are the best study materials for students who are finding difficulties in solving problems. Students can refer to and download the PDF of RD Sharma Solutions for Class 7 Maths, Chapter 13 Simple Interest from the given links. The solutions to all questions in RD Sharma Solutions for Class 7 are given here in a detailed and step-by-step way to help students understand the concepts more effectively. Chapter 13 Simple Interest is based on general transactions with interest. RD Sharma Solutions cover all the topics related to it. Some of the important topics discussed in the chapter are listed below.
- Definition of principal
- Definition and meaning of interest
- Formula to calculate the amount
- Definition and meaning of simple interest
- Formula to calculate simple interest
- Verbally related problems on simple interest
RD Sharma Solutions for Class 7 Maths Chapter 13 Simple Interest
Access answers to Maths RD Sharma Solutions For Class 7 Chapter 13 – Simple Interest
1. Find the simple interest, when:
(i) Principal = Rs 2000, Rate of Interest = 5% per annum and Time = 5 years.
(ii) Principal = Rs 500, Rate of Interest = 12.5% per annum and Time = 4 years.
(iii) Principal = Rs 4500, Rate of Interest = 4% per annum and Time = 6 months.
(iv) Principal = Rs 12000, Rate of Interest = 18% per annum and Time = 4 months.
(v) Principal = Rs 1000, Rate of Interest = 10% per annum and Time = 73 days.
Solution:
(i) Given Principal = Rs 2000, Rate of Interest = 5% per annum and Time = 5 years.
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (2000 × 5 × 5)/100
= Rs 500
(ii) Given Principal = Rs 500, Rate of Interest = 12.5% per annum and Time = 4 years.
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (500 × 4 × 12.5)/100
= Rs 250
(iii) Given Principal = Rs 4500, Rate of Interest = 4% per annum and Time = 6 months = ½ years
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (4500 × ½ × 4)/100
SI = (4500 × 1 × 4)/100 × 2
= Rs 90
(iv) Given Principal = Rs 12000, Rate of Interest = 18% per annum and Time = 4 months = (4/12) = (1/3) years
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (12000 × (1/3) × 18)/100
SI = (12000 × 1 × 18)/100 × 3
= Rs 720
(v) Given Principal = Rs 1000, Rate of Interest = 10% per annum and
Time = 73 days = (73/365) days
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (1000 × (73/365) × 10)/100
SI = (1000 × 73 × 10)/100 × 365
= Rs 20
2. Find the interest on Rs 500 for a period of 4 years at the rate of 8% per annum. Also, find the amount to be paid at the end of the period.
Solution:
Given Principal amount P = Rs 500
Time period T = 4 years
Rate of interest R = 8% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (500 × 4 × 8)/100
= Rs 160
Amount = Principal amount + Interest
= Rs 500 + 160
= Rs 660
3. A sum of Rs 400 is lent at the rate of 5% per annum. Find the interest at the end of 2 years.
Solution:
Given Principal amount P = Rs 400
Time period T = 2 years
Rate of interest R = 5% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (400 × 2 × 5)/100
= Rs 40
4. A sum of Rs 400 is lent for 3 years at the rate of 6% per annum. Find the interest.
Solution:
Principal amount P = Rs 400
Time period T = 3 years
Rate of interest R = 6% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (400 × 3 × 6)/100
= Rs 72
5. A person deposits Rs 25000 in a firm who pays an interest at the rate of 20% per annum. Calculate the income he gets from it annually.
Solution:
Given Principal amount P = Rs 25000
Time period T = 1 year
Rate of interest R = 20% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (25000 × 1 × 20)/100
= Rs 5000
6. A man borrowed Rs 8000 from a bank at 8% per annum. Find the amount he has to pay after 4 ½ years.
Solution:
Given Principal amount P = Rs 8000
Time period T = 4 ½ years = 9/2 years
Rate of interest R = 8% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (8000 × (9/2) × 8)/100
= Rs 2880
Amount = Principal amount + Interest
= Rs 8000 + 2880
= Rs 10880
7. Rakesh lent out Rs 8000 for 5 years at 15% per annum and borrowed Rs 6000 for 3 years at 12% per annum. How much did he gain or lose?
Solution:
Given Principal amount P = Rs 8000
Time period T = 5 years
Rate of interest R = 15% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (8000 × 5 × 15)/100
= Rs 6000
Principal amount P = Rs 6000
Time period T = 3 years
Rate of interest R = 12% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (6000 × 3 × 12)/100
= Rs 2160
Amount gained by Rakesh = Rs 6000 − Rs 2160
= Rs 3840
8. Anita deposits Rs 1000 in a savings bank account. The bank pays interest at the rate of 5% per annum. What amount can Anita get after one year?
Solution:
Given Principal amount P = Rs 1000
Time period T = 1 year
Rate of interest R = 5% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (1000 × 1 × 5)/100
= Rs 50
Total amount paid after 1 year = Principal amount + Interest
= Rs 1000 + Rs 50
= Rs 1050
9. Nalini borrowed Rs 550 from her friend at 8% per annum. She returned the amount after 6 months. How much did she pay?
Solution:
Given Principal amount P = Rs 550
Time period T = ½ year
Rate of interest R = 8% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (550 × ½ × 8)/100
= Rs 22
Total amount paid after ½ year = Principal amount + Interest
= Rs 550 + Rs 22
= Rs 572
10. Rohit borrowed Rs 60000 from a bank at 9% per annum for 2 years. He lent this sum of money to Rohan at 10% per annum for 2 years. How much did Rohit earn from this transaction?
Solution:
Given Principal amount P = Rs 60000
Time period T = 2 years
Rate of interest R = 10% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (60000 × 2 × 10)/100
= Rs 12000
Principal amount P = Rs 60000
Time period T = 2 years
Rate of interest R = 9% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (60000 × 2 × 9)/100
= Rs 10800
Amount gained by Rohit = Rs 12000 − Rs 10800
= Rs 1200
11. Romesh borrowed Rs 2000 at 2% per annum and Rs 1000 at 5% per annum. He cleared his debt after 2 years by giving Rs 2800 and a watch. What is the cost of the watch?
Solution:
Given Principal amount P = Rs 2000
Time period T = 2 years
Rate of interest R = 2% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (2000 × 2 × 2)/100
= Rs 80
Principal amount P = Rs 1000
Time period T = 2 years
Rate of interest R = 5% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (1000 × 2 × 5)/100
= Rs 100
Total amount that he will have to return = Rs. 2000 + 1000 + 80 + 100 = Rs. 3180
Amount repaid = Rs. 2800
Value of the watch = Rs. 3180 – 2800 = Rs. 380
12. Mr Garg lent Rs 15000 to his friend. He charged 15% per annum on Rs 12500 and 18% on the rest. How much interest does he earn in 3 years?
Solution:
Given Principal amount P = Rs 12500
Time period T = 3 years
Rate of interest R = 15% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (12500 × 3 × 15)/100
= Rs 5625
Rest of the amount lent = Rs 15000 − Rs 12500 = Rs 2500
Rate of interest = 18 % p.a.
Time period = 3 years
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (2500 × 3 × 18)/100
= Rs 1350
Total interest earned = Rs 5625 + Rs 1350 = Rs 6975
13. Shikha deposited Rs 2000 in a bank which pays 6% simple interest. She withdrew Rs 700 at the end of first year. What will be her balance after 3 years?
Solution:
Given Principal amount P = Rs 2000
Time period T = 1 year
Rate of interest R = 6% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (2000 × 1 × 6)/100
= Rs 120
So amount after 1 year = Principal amount + Interest = 2000 + 120 = Rs 2120
after 1 year, amount withdrawn = Rs 700
Principal amount left = Rs 2120 − Rs 700 = Rs 1420
Time period = 2 years
Rate of interest = 6% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (1420 × 2 × 6)/100
Interest after two years = Rs 170.40
Total amount after 3 years = Rs 1420 + Rs 170.40 = Rs 1590.40
14. Reema took a loan of Rs 8000 from a money lender, who charged interest at the rate of 18% per annum. After 2 years, Reema paid him Rs 10400 and wrist watch to clear the debt. What is the price of the watch?
Solution:
Given Principal amount P = Rs 8000
Time period T = 2 years
Rate of interest R = 18% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (8000 × 2 × 18)/100
= Rs 2880
Total amount payable by Reema after 2 years = Rs 8,000 + Rs 2,880
= Rs 10,880
Amount paid = Rs 10,400
Value of the watch = Rs 10,880 − Rs 10,400 = Rs 480
15. Mr Sharma deposited Rs 20000 as a fixed deposit in a bank at 10% per annual. If 30% is deducted as income tax on the interest earned, find his annual income.
Solution:
Given Principal amount P = Rs 20000
Time period T = 1 year
Rate of interest R = 10% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in the above equation, we get
SI = (20000 × 1 × 10)/100
= Rs 2000
Amount deducted as income tax = 30% of 2000 = (30 × 2000)/100
= Rs 600
Annual interest after tax deduction = Rs 2,000 − Rs 600 = Rs 1,400
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