RS Aggarwal Solutions for Class 7 Maths Chapter 13 – Lines and Angles are available here. These exercises are formulated by our expert tutors in order to assist you with your exam preparation to attain good marks in Maths. Students who wish to score good marks in Maths practise RS Aggarwal Class 7 Solutions. This book is one of the top materials when it comes to providing a question bank to practice from.

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### Access answer to chapter 13 – Lines and Angles

__Exercise 13__

**1. Find the complement of each of the following angles:**

**(i). 35 ^{o}**

**Solution:-**

Two angles are said to be complementary if the sum of their measures is 90^{o}.

The given angle is 35^{o}

Let the measure of its complement be x^{o}.

Then,

= x + 35 = 90

= x = 90 â€“ 35

= x = 55^{o}

Hence, the complement of the given angle measures 55^{o}.

**(ii). 47 ^{o}**

**Solution:-**

Two angles are said to be complementary if the sum of their measures is 90^{o}.

The given angle is 47^{o}

Let the measure of its complement be x^{o}.

Then,

= x + 47 = 90

= x = 90 â€“ 47

= x = 43^{o}

Hence, the complement of the given angle measures 43^{o}.

**(iii). 60 ^{o}**

**Solution:-**

Two angles are said to be complementary if the sum of their measures is 90^{o}.

The given angle is 60^{o}

Let the measure of its complement be x^{o}.

Then,

= x + 60 = 90

= x = 90 â€“ 60

= x = 30^{o}

Hence, the complement of the given angle measures 30^{o}.

**(iv). 73 ^{o}**

**Solution:-**

Two angles are said to be complementary if the sum of their measures is 90^{o}.

The given angle is 73^{o}

Let the measure of its complement be x^{o}.

Then,

= x + 73 = 90

= x = 90 â€“ 73

= x = 17^{o}

Hence, the complement of the given angle measures 17^{o}.

**2. Find the supplement of each of the following angles:**

**(i). 80 ^{o}**

**Solution:-**

Two angles are said to be supplementary if the sum of their measures is 180^{o}.

The given angle is 80^{o}

Let the measure of its supplement be x^{o}.

Then,

= x + 80 = 180

= x = 180 â€“ 80

= x = 100^{o}

Hence, the supplement of the given angle measures 100^{o}.

**(ii). 54 ^{o}**

**Solution:-**

Two angles are said to be supplementary if the sum of their measures is 180^{o}.

The given angle is 54^{o}

Let the measure of its supplementary be x^{o}.

Then,

= x + 54 = 180

= x = 180 â€“ 54

= x = 126^{o}

Hence, the supplementary of the given angle measures 126^{o}.

**(iii). 105 ^{o}**

**Solution:-**

Two angles are said to be supplementary if the sum of their measures is 180^{o}.

The given angle is 105^{o}

Let the measure of its supplementary be x^{o}.

Then,

= x + 105 = 180

= x = 180 â€“ 105

= x = 75^{o}

Hence, the supplementary of the given angle measures 75^{o}.

**(iv). 123 ^{o}**

**Solution:-**

Two angles are said to be supplementary if the sum of their measures is 180^{o}.

The given angle is 123^{o}

Let the measure of its supplementary be x^{o}.

Then,

= x + 123 = 180

= x = 180 â€“ 123

= x = 57^{o}

Hence, the supplementary of the given angle measures 57^{o}.

**3. Among two supplementary angles, the measures of the larger angle is 36 ^{o} more than the measure of the smaller. Find their measures.**

**Solution:-**

Let us assume supplementary angles be x^{o} and (180 â€“ x)^{o}

From the question,

The measures of the larger angle is 36^{o} more than the measure of the smaller angle, let the larger angle be x^{o.}

Then,

= (180 â€“ x) + 36 = x

= 216 â€“ x = x

= 216 = x + x

= 216 = 2x

= x = 216/2

= x = 108

Larger angle = 108^{0}

Smaller angle = (108 â€“ 36)^{o}

= 72

**4. Find the angle which is equal to its supplement.**

**Solution:-**

Let the measure of the required angle be x^{o}.

Then,

= x + x = 180^{o}

= 2x = 180^{o}

= x = 180/2

= x = 90^{o}

Hence, the required angle measures 90^{o}.

**5. Can two angles be supplementary if both of them are?**

**(i). Acute?**

**Solution:-**

No. If two angles are acute, means less than 90^{o}, the two angles cannot be supplementary. Because, their sum will be always less than 90^{o}.

**(ii). Obtuse?**

**Solution:-**

No. If two angles are obtuse, means more than 90^{o}, the two angles cannot be supplementary. Because, their sum will be always more than 180^{o}.

**(iii). Right?**

**Solution:-**

Yes. If two angles are right, means both measures 90^{o}, then two angles can form a supplementary pair.

âˆ´90^{o }+ 90^{o} = 180

## RS Aggarwal Solutions for Class 7 Maths Chapter 13 – Lines and Angles

Chapter 13 – Lines and Angles contains 1 exercise and the RS Aggarwal Solutions available on this page provide solutions to the questions present in the exercises. Now, let us have a look at some of the concepts discussed in this chapter.

- Supplementary Angles
- Complementary Angles
- Adjacent Angles
- Linear Pair of Angles
- Vertically opposite Angles

### Chapter Brief of RS Aggarwal Solutions for Class 7 Maths Chapter 13 – Lines and Angles

RS Aggarwal Solutions for Class 7 Maths Chapter 13 – Lines and Angles. In Class 6, students learn about angles and their measurements. Now, students learn about some properties of angles and also learn how to find complementary angles and supplementary angles. The main points to be remembered by the students are, the sum of all angles formed on the same side of a line at a given point on the line is 180 degrees, and the sum of all angles around a point is 360 degrees.