# RS Aggarwal Solutions for Class 7 Maths Exercise 5B Chapter 5 Exponents

RS Aggarwal Solutions for Class 7 Maths Exercise 5B Chapter 5 Exponents, the RS Aggarwal is an essential material as it offers a wide range of questions that test the students understanding of concepts. This exercise contains expressing large numbers in standard form; a given number is said to be standard form if it can be expressed as kÃ—(10 to the power of n). Our expert personnel have solved the problems step by step with neat explanations. Students can download the PDF of RS Aggarwal Solutions for Class 7 Maths Chapter 5 Exponents. Students gain more knowledge by referring to RS Aggarwal Class 7 Solutions.

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1. Express each of the following numbers in standard form:

(i) 538

Solution:-

A given number is said to be in standard form if it can be expressed as k Ã— 10n, where k is a real number such that 1 â‰¤ k < 10and n is a positive integer.

Then,

538 = 5.38 Ã— 102

(ii) 6428000

Solution:-

A given number is said to be in standard form if it can be expressed as k Ã— 10n, where k is a real number such that 1 â‰¤ k < 10and n is a positive integer.

Then,

6428000 = 6.428 Ã— 106

(iii) 82934000000

Solution:-

A given number is said to be in standard form if it can be expressed as k Ã— 10n, where k is a real number such that 1 â‰¤ k < 10and n is a positive integer.

Then,

82934000000 = 8.2934 Ã— 1010

(iv) 940000000000

Solution:-

A given number is said to be in standard form if it can be expressed as k Ã— 10n, where k is a real number such that 1 â‰¤ k < 10and n is a positive integer.

Then,

940000000000 = 9.4 Ã— 1011

(v) 23000000

Solution:-

A given number is said to be in standard form if it can be expressed as k Ã— 10n, where k is a real number such that 1 â‰¤ k < 10and n is a positive integer.

Then,

23000000 = 2.3 Ã— 107

2. Express each of the following numbers in standard form:

(i) Diameter of Earth = 12756000 m

Solution:-

A given number is said to be in standard form if it can be expressed as k Ã— 10n, where k is a real number such that 1 â‰¤ k < 10and n is a positive integer.

Then,

Diameter of Earth = 12756000 m

= (1.2156 Ã— 107) m (in standard form)

(ii) Distance between Earth and Moon = 384000000 m

Solution:-

A given number is said to be in standard form if it can be expressed as k Ã— 10n, where k is a real number such that 1 â‰¤ k < 10and n is a positive integer.

Then,

Distance between Earth and Moon = 384000000 m

= (3.84 Ã— 108) m (in standard form)

(iii) Population of India in March 2001= 1027000000

Solution:-

A given number is said to be in standard form if it can be expressed as k Ã— 10n, where k is a real number such that 1 â‰¤ k < 10and n is a positive integer.

Then,

Population of India in March 2001= 1027000000

= (1.027 Ã— 109) (in standard form)

(iv) Number of stars in a galaxy = 100000000000

Solution:-

A given number is said to be in standard form if it can be expressed as k Ã— 10n, where k is a real number such that 1 â‰¤ k < 10and n is a positive integer.

Then,

Number of stars in a galaxy = 100000000000

= (1 Ã— 1011) (in standard form)

(v) The present age of universe = 12000000000 years

Solution:-

A given number is said to be in standard form if it can be expressed as k Ã— 10n, where k is a real number such that 1 â‰¤ k < 10and n is a positive integer.

Then,

The present age of universe = 12000000000

= (1.2 Ã— 1010) years (in standard form)

### Access other exercises of RS Aggarwal Solutions For Class 7 Chapter 5 – Exponents

Exercise 5C Solutions