RS Aggarwal Solutions for Class 8 Chapter 24 - Pie Charts

RS Aggarwal Solutions for Class 8 Maths Chapter 24- Pie Charts, are provided here. Our expert faculty team has prepared solutions in order to help you with your exam preparation to acquire good marks in Maths. RS Aggarwal Solutions book for Class 8 Maths comes in very handy at this point. Our solution module utilizes various shortcut tips and practical examples to explain all the exercise questions in a simple and easily understandable language. Practicing the textbook questions will help you in analyzing your level of preparation and knowledge of the concept.
In order to help you understand and solve the problems, we at BYJU’S have designed these solutions in a very lucid and clear manner that helps students solve problems in the most efficient possible ways. Here is the RS Aggarwal Solutions for Class 8 Chapter 24 where solutions are solved in detail. Download pdf of Class 8 Chapter 24 in their respective links.

RS Aggarwal Solutions for Class 8 Maths Chapter 24- Pie Charts, are provided here. Our solution module utilizes various shortcut tips and practical examples to explain all the exercise questions in a simple and easily understandable language. Our expert faculty team at BYJU’S has designed these solutions in a very lucid and clear manner that helps students solve problems without any difficulty. Students can easily refer and download pdf of RS Aggarwal Class 8 Maths Solutions book and start practising the textbook questions which will help you in securing high marks in your examination.

Download PDF of RS Aggarwal Solutions for Class 8 Maths Chapter 24 – Pie Charts

rs aggarwal solutions class 8 maths chapter 24a
rs aggarwal solutions class 8 maths chapter 24a
rs aggarwal solutions class 8 maths chapter 24a
rs aggarwal solutions class 8 maths chapter 24a
rs aggarwal solutions class 8 maths chapter 24a
rs aggarwal solutions class 8 maths chapter 24a
rs aggarwal solutions class 8 maths chapter 24a
rs aggarwal solutions class 8 maths chapter 24a
rs aggarwal solutions class 8 maths chapter 24b

Access answers to Chapter 24 – Pie Charts

Exercise 24A
1. The monthly income of a family is ₹28800. The monthly expenditure of the family on various items is given below.

Items Rent Food Clothing Education Savings
Expenditure
(in ₹)
8000 10800 5600 3600 800

Represent the above data by a pie chart.
Solution: We know that the,
Total monthly income = ₹28800
By using the formula,
Central angle of component = ((value of the component)/Total value) × 360o
So, the Calculations are

Items Expenditure(in ₹ ) Central angle
Rent 8000 (8000/28800) × 360o = 100o
Food 10800 (10800/28800) × 360o = 135o
Clothing 5600 (5600/28800) × 360o = 70o
Education 3600 (3600/28800) × 360o = 45o
Savings 800 (800/28800) × 360o = 10o

∴ we can represent the above data in pie chart as:
RS Aggarwal Class 8 Chapter 24 Pie Charts-solution-1
2. There are 900 creatures in a zoo as per list given below:

Beast animals Other land animals Birds Water animals Reptiles
150 400 175 125 50

Represent the above data by a pie chart.
Solution: We know that the,
Total animals =900
By using the formula,
Central angle of component = ((value of the component)/Total value) × 360o
So, the Calculations are

Animals Number of animals Central angle
Beast animals 150 (150/900) × 360o = 60o
Other land animals 400 (400/900) × 360o = 160o
Birds 175 (175/900) × 360o = 70o
Water animals 125 (125/900) × 360o = 50o
Reptiles 50 (50/900) × 360o = 20o

∴ we can represent the above data in pie chart as:
RS Aggarwal Class 8 Chapter 24 Pie Charts-solution-2
3. Various modes of transport used by 1260 students in a given school are given below:

School bus Private bus Bicycle Rickshaw On foot
350 245 210 175 280

Represent the above data by a pie chart.
Solution: We know that the,
Total students =1260
By using the formula,
Central angle of component = ((value of the component)/Total value) × 360o
So, the Calculations are

Mode of transport Number of students Central angle
School bus 350 (350/1260) × 360o = 100o
Private bus 245 (245/1260) × 360o = 70o
Bicycle 210 (210/1260) × 360o = 60o
Rickshaw 175 (175/1260) × 360o = 50o
On foot 280 (280/1260) × 360o = 80o

∴ we can represent the above data in pie chart as:
RS Aggarwal Class 8 Chapter 24 Pie Charts-solution-3
4. The data given below shows number of hours spent by a school boy on different activities on a working day.

Activity School Homework Play Sleep Others Total
Number of hours 7 4 2 8 3 24

Represent the above data by a pie chart.
Solution: We know that the,
Total number of hours =24
By using the formula,
Central angle of component = ((value of the component)/Total value) × 360o
So, the Calculations are

Activity Number of hours Central angle
School 7 (7/24) × 360o = 105o
Homework 4 (4/24) × 360o = 60o
Play 2 (2/24) × 360o = 30o
Sleep 8 (8/24) × 360o = 120o
Others 3 (3/24) × 360o = 45o

∴ we can represent the above data in pie chart as:
RS Aggarwal Class 8 Chapter 24 Pie Charts-solution-4
5. The data on religion wise division of 1080 workers of a factory are given below:

Religion Hindu Muslim Sikh Christian
Number of workers 450 270 255 105

Represent the above data by a pie chart.
Solution: We know that the,
Total number of workers =1080
By using the formula,
Central angle of component = ((value of the component)/Total value) × 360o
So, the Calculations are

Religion Number of workers Central angle
Hindu 450 (450/1080) × 360o = 150o
Muslim 270 (270/1080) × 360o = 90o
sikh 255 (255/1080) × 360o = 80o
Christian 105 (105/1080) × 360o = 35o

∴ we can represent the above data in pie chart as:
RS Aggarwal Class 8 Chapter 24 Pie Charts-solution-5
Exercise 24B
OBJECTIVE QUESTIONS
Select the correct answer in each of the following:
1. A man’s monthly salary is ₹24000 and his monthly expenses on travel are ₹2500. The central angle of the sector representing travel expenses in the pie chart would be

  1. 30o
  2. 37 ½ o
  3. 45o
  4. 60o

Solution: We know that the monthly salary = ₹24000
Monthly expense on travel = ₹2500
By using the formula,
Central angle of component = ((value of the component)/Total value) × 360o
= (2500 / 24000) × 360o
= 37.5o = 37 ½ o
2. If 35% of the people residing in a locality are Sikhs then the central angle of the sector representing the Sikh community in the pie chart would be

  1. 108o
  2. 115o
  3. 126o
  4. 135o

Solution: We know that the total people residing in locality = 100 %
Sikh people residing in the same locality = 35%
By using the formula,
Central angle of component = ((value of the component)/Total value) × 360o
= (35 / 100) × 360o
= 126o

RS Aggarwal Solutions for Class 8 Maths Chapter 24 – Pie Charts

Chapter 24- Pie Charts contains 2 exercises and the RS Aggarwal solutions present on this page provide the solutions for the questions present in each exercise. Now, let us have a look at the concepts discussed in this chapter.

  • Calculating Central Angle for a component.
  • Construction of a Pie Chart for a given data.

Also, Access RS Aggarwal Solutions for Class 8 Chapter 24 Exercises

Exercise 24A
Exercise 24B

Chapter Brief of RS Aggarwal Solutions for Class 8 Maths Chapter 24 – Pie Charts

RS Aggarwal Solutions for Class 8 Maths Chapter 24 – Pie Charts, The solutions are designed in such a way that they are easy to understand and solve. By regular revision, the concepts become more clear and can score well in their exams.

As the Chapter is about Pie Charts, here we calculate the Central angle for a component then we draw a Pie Chart based on the results obtained. In the RS Aggarwal Solutions book, many such exercise problems are provided.