 # RS Aggarwal Class 9 Solutions Chapter 2 - Polynomials

## RS Aggarwal Class 9 Chapter 2 - Polynomials Solutions Free PDF

A mathematical expression containing variables, coefficients along with integer exponents, which are not negative is called Polynomial. Polynomial equations are primarily used to describe polynomial functions and are primarily used in areas of mathematics and science. The different fields that polynomials are used for are:

• Physics
• Chemistry
• Social Science
• Economics
• Calculus
• Numerical Analysis
• Algebraic Geometry

The different types of Polynomials are:

1. Matrix Polynomials
2. Trigonometric Polynomials
3. Rational Functions
4. Laurent Polynomials
5. Power Series

## Download PDF of RS Aggarwal Class 9 Chapter 2 – Polynomials

We have provided below the RS Aggarwal Class 9 solutions Chapter 2 for students so that they can refer to it whenever they have any doubt and also cross-check their solving methods. The solutions are provided in pdf format so that students can download it for future reference. It acts as a reference guide for Class 9 students.

Question 1:

Which of the following expressions are polynomials?

(i) x5 -2x3 + x+7

It is a polynomial, Degree = 5.

(ii) y3 3y$\sqrt{3}y$

It is polynomial, Degree = 3.

(iii) t225t+2$\frac{2}{5}t+\sqrt{2}$

It is polynomial, Degree = 2.

(iv) 5z6$5\sqrt{z}-6$

It is not a polynomial.

(v) x1x$x-\frac{1}{x}$

It is not a polynomial.

(vi) x1081$x^{108}-1$

It is polynomial, Degree = 108.

(vii) x327$\sqrt{x}-27$

It is not a polynomial.

(viii) 12x22x+2$\frac{1}{\sqrt{2}}x^{2}-\sqrt{2}x+2$

It is a polynomial, Degree = 2.

(ix) x2+2x1+3$x^{-2}+2x^{-1}+3$

It is not a polynomial.

(x) 1

It is a polynomial, Degree = 0.

(xi) –35$\frac{3}{5}$

It is a polynomial, Degree = 0.

(xii) 23y28$\sqrt{2}y^{2}-8$

It is a polynomial, Degree = 2.

Question 2:

Write the degree of each of the following polynomials:

The degree of a polynomial in one variable is the highest power of the variable.

(i)2x-5$\sqrt{5}$

Degree of 2x – 5$\sqrt{5}$ is 1.

(ii) 3 – x + x2-6x3

Degree of 3 – x + x2– 6x3 is 3.

(iii)9

Degree of 9 is 0.

(iv) 8x4-36x+5x7

Degree of 8x4 – 36x + 5x7 is 7.

(v)x9-x5+3x10+8

Degree of x9 – x5 3x10 + 8 is 10.

(vi) 2-3x2

Degree of 2 – 3x2 is 2.

Question 3:

Write :

(i) Coefficient of x3 in 2x + x2 – 5x3+ x4

-5

(ii) Coefficient of x in 3$\sqrt{3}$ – 22x$\sqrt{2x}$ + 4x2

— 22$\sqrt{2}$

(iii) Coefficient of x2 in ÷3$\prod \div 3$ x2 + 7x-3

÷3$\prod \div 3$

(iv)   Coefficient of x2 in 3x – 5

0.

Question 4:

(i) Give an example of a binomial of degree 27.

x27 — 36

(ii) Give an example of a monomial of degree 16.

y116

(iii) Give an example of a trinomial of degree 3.

5x3 — 8x + 7

Question 5:

Classify the following as linear, quadratic and cubic polynomials :

(i)               2x2 + 4x

It is a quadratic polynomial.

(ii)         x – x3

It is a cubic polynomial.

(iii)       2 – y – y2

It is a quadratic polynomial.

(iv)   -7 + z

It is a linear polynomial.

(v)     5t

It is a linear polynomial.

(vi)    p3

It is a cubic polynomial.

Question 6:

If p(x) = 5 – 4x + 2x2, find

(i) p(0)

= 5 – 4(0) + 2(0)2

= 5

(ii) p(3)

= 5 – 4(3) + 2(3)2

= 5 – 12 + 18

= 23 – 12

= 11

(iii) p(-2)

= 5 – 4(-2) + 2(-2)2

= 5 + 8 + 8

= 21

Question 7:

If P(Y) = 4 + 3Y – Y2+ 5y3 , find

(i) p(0)

= 4 + 3(0) – 02 + 5(0)3

= 4 + 0 – 0 + 0

= 4

(ii) p(2)

= 4 + 3(2) – 22 + 5(2)3

= 4 + 6 – 4 + 40

= 10 – 4 + 40

= 46

(III) p(-1)

= 4 + 3(-1) – (-1)2 + 5(-1)3

= 4 – 3 – 1 – 5

= -5

Question 8:

If f(t) = 4t2 – 3t + 6, find

(i) f(0)

= 4(0)2 – 3(0) + 6

= 0 – 0 + 6

= 6

(ii) f(4)

= 4(4)2 – 3(4) + 6

= 64 – 12 + 6

= 58

(iii) f(-5)

= 4(-5)2 – 3(-5) + 6

= 100 + 15 + 6

= 121

### RS Aggarwal Class 9 Solutions Chapter 2– Polynomials

The main objective of the RS Aggarwal Maths solution is to help students to improve their understanding of difficult concepts of maths. These solutions help in revising different topics in quick time before the exam. Prepared by subject experts these solutions completely follow the latest CBSE syllabus. The RS Aggarwal Class 9 Solutions Chapter 2 are easy to understand as it is solved in a very simple language. These solutions need to practice on a daily basis if you want to score good marks in your exam.

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