0.4g of an organic compound gave 0.188g of silver bromide by a halogen estimation method. The percentage of bromine in the compound is:(Atomic mass of Ag = 108, Br= 80).

The correct option is A

20%

The explanation for the correct option

Option (A) 20%

Step 1: Given data

According to the question,

Mass of the compound = 0.4g

Mass of $\mathrm{AgBr}$ = 0.188g

Step 2: Formula used for estimation of bromine in an organic compound.

The formula for the estimation of bromine is:

$\mathrm{Percentage}\mathrm{of}\mathrm{Br}=\frac{80}{188}\times \frac{\mathrm{Mass}\mathrm{of}\mathrm{AgBr}\times 100}{\mathrm{Mass}\mathrm{of}\mathrm{compound}}$

Step 3: Put the given values into the formula.

Putting the values in the formula,

$\mathrm{Percentage}\mathrm{of}\mathrm{Br}=\frac{80}{188}\times \frac{0.188\times 100}{0.4}=20\%$

Therefore, 20% of Bromine is present in the compound.

Hence option A is correct.