# Titration

A titration can define the volume of one solution required to react correctly with an identified volume of a different solution. Titration commonly comprises of reactions such as redox reactions and reactions involving precipitations, different than acid-base reactions.

**“Titration can discern the volume of one solution required to react exactly with a known volume of a different solution.”**

The equation for Titration Formula is articulated as:

Where,

1000 = factor relating mg to grams

W = mass of sample

N = normality of titrant

V = volume of titrant

Eq.wt = equivalent weight of acid

Though commonly the Titration Formula is articulated as:

Where,

V1 = Volume of titrant

N = Normality of titrant

V2 = Volume of sample

Eq.wt = equivalent weight of predominant acid

**Solved Examples**

**Problem 1**: Compute the titratable acidity if 17.5ml of 0.085N NaOH is required to titrate a 15ml sample of juice, the sum titratable acidity of that juice, articulated as percent citric acid. (molecular weight = 192; equivalent weight = 64)

**Solution:**

Now we use the equation:

% of acid = 0.085×17.5×64/15×10 = 0.635%

Notice that the equivalent weight of anhydrous citric acid always is used in calculating and reporting the results of titration.

**Problem 2**: Contemplate the reaction of sulfuric acid H2SO4 with sodium hydroxide NaOH.

H2SO4 + 2NaOH à 2H2O + Na2SO4

How many millimeters of 0.250M NaOH must be added to react completely with the sulfuric acid? Assuming that a beaker contains 35.0mL of 0.175M H2SO4.

**Answer:**

The calculation is as follows.

= 4.90 ×× 10-2 L NaOH

precisely 49.0 mL of 0.250M sodium hydroxide solution reacts with 35.0 mL of 0.175M sulfuric acid solution.