Two step Addition and Subtraction (Definition, Types and Examples) - BYJUS

# Two-step Addition and Subtraction

Some real-life problems related to math cannot be solved in a single step. In such cases, we break down the questions using different strategies and find out the solution. Learn how to solve such real-life math problems related to addition and subtraction....Read MoreRead Less ## Solving Word problems

Solving problems related to addition and subtraction is made easier by observing aspects of a problem. For this, you need to consider the following questions.

• What is given?

First, we need to identify the data that has been provided.

• What to find out?

Then, we need to figure out what we need to calculate.

• How do we find out?

Finally, we need to analyze which method of operation has to be carried out with the given values so that we can arrive at the required answer.

For example:

Example 1:

Liam has 1000 books in his library. If he bought 500 more and gave away 300 books, how many books does he have in his library now?

Solution:

Understand the problem

What is given?

• Liam has 1000 books.
• He bought 500 more.
• He gave away 300 books.

What to find out?

• How many books does Liam have now?

How will you solve it?

• Add 1000 and 500 to find out how many books Liam has.
• Then subtract 300 from the sum to find out how many books Liam has now.

Step 1

Let k be the initial number of books.

k = 1000 + 500 Step 2: Let n be the unknown difference after Liam gave away 300 books.

$$n-k=300$$

$$\Rightarrow n~=~1500-300$$ $$\therefore n~=~1200$$

So, Liam has a total of 1200 books in his library.

## Solved Examples

Example 1:

Harry has 10 pencils. He bought 5 more pencils.

If he has used 2 pencils, how many pencils are left with him?

Solution:

Initially, Liam had 10 pencils, and later he bought 5 more.

Liam has 10 + 5 = 15 pencils.

Since Liam has used 2 pencils.

The number of pencils he still has is,

= 15 – 2

= 13

Example 2:

Leah and Jay decide to play a game. They need to fill a huge container each with as many items as possible so that one container weighs more than the other. The container that weighs the most wins. It is known that Leah’s container weighs 542 pounds, and both containers weigh 1276 pounds together. By what difference does the winner win?

Solution:

Let the weight of Jay’s container be x pounds.

Since both containers weigh 1276 pounds, the weight of Jay’s container can be given as,

$$x=1276-542$$ $$x~=~734$$

734 > 542.

734 – 542 Hence, Jay wins the contest by 192 pounds.

Example 3:

A construction company uses 200 fewer rods in constructing building A than building B. There were 624 rods used in building B and 721 rods were used in constructing C. How many rods does the company use to construct building A? Also, find the total number of rods that were used for all three buildings.

Buildings

Rods used

A

?

B

624

C

721

Solution:

Step 1: How many rods are used in building A?

Let $$x$$ be the number of rods used in building A

Then,

$$x~=~624-200$$ $$x~=~424$$

Step 2: Find the total number of rods used in all three buildings.

Let $$y$$ be the total number of rods used in the three buildings.

Then,

$$y~=~x+624+721$$

$$y~=~424+624+721$$ $$\therefore y~=~1769$$

So, the total number of rods used in all three buildings is 1769.