Anova Formula

Analysis of variance, or ANOVA, is a strong statistical technique that is used to show the difference between two or more means or components through significance tests. It also shows us a way to make multiple comparisons of several populations means. The Anova test is performed by comparing two types of variation, the variation between the sample means, as well as the variation within each of the samples. The below mentioned formula represents one-way Anova test statistics:
Alternatively,
F = MST/MSE
MST = SST/ p-1
MSE = SSE/N-p
SSE = ∑ (n−1)$s^{2}$

Where,

F = Anova Coefficient

MSB = Mean sum of squares between the groups

MSW = Mean sum of squares within the groups

MSE = Mean sum of squares due to error

SST = total Sum of squares

p = Total number of populations

n = The total number of samples in a population

SSW = Sum of squares within the groups

SSB = Sum of squares between the groups

SSE = Sum of squares due to error

s = Standard deviation of the samples

N = Total number of observations

Solved Examples

For reference please go through the below-mentioned example:

Question 1: 

The following data is given:

Types of Animals  Number of animals Average Domestic animals Standard Deviation
Dogs 12
Cats 5 16
Hamsters  20 


Calculate the Anova coefficient.

Solution:

 Construct the following table:

Animal name   n       x       s      $s^{2}$ 
Dogs 12 2 4
Cats  5 16 
Hamster 5 20 16 


p = 3
n = 5
N = 15
x̄ = 16
SST = ∑n (x−x̄)2
SST= 5(12−16)2+5(16−16)2+11(20−16)2
= 160

MST = $\frac{SST}{p−1}$

MST = $\frac{160}{3−1}$

MST = 80

SSE = ∑ (n−1)$s^{2}$

SSE = 4$\times$4 + 4$\times$1 + 4$\times$16

SSE = 84

MSE= $\frac{SSE}{N−p}$

MSE=$\frac{8415}{38415−3}$

MSE = 7

F = $\frac{MST}{MSE}$ 

F = $\frac{80}{7}$

F = 11.429

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