The chapter 6 of class 10 physical science refraction of light at curved surfaces, discusses the refraction of light at curved surfaces.
Important Formulas in Chapter 6 Refraction of Light at Curved Surfaces
- The formula used when a light ray enters a medium with refractive index n_{2} from a medium with refractive index n_{1} at curved interface with a radius of curvature R is given as follows:
\(\frac{n_2}{v}-\frac{n_1}{v}=\frac{n_2-n_1}{R}\)
- The lens formula is given as
\(\frac{1}{f}=\frac{1}{v}-\frac{1}{u}\)
where u is the object distance, f is the focal length of the lens and v is the image distance
- The lens makerâ€™s formula is given as
\(\frac{1}{f}=(n-1)(\frac{1}{R_1}-\frac{1}{R_2})\)
where n is the refractive index, R_{1 }and R_{2} are radii of curvature and f is the focal length
In the next section, let us look at a few chapter questions to better understand the concepts discussed in the chapter.
Chapter 6 Refraction of Light at Curved Surfaces Questions
- How do you verify experimentally that the focal length of a convex lens is increased when it is kept in water?
- A double convex lens has two surfaces of equal radii â€˜Râ€™ and refractive index n = 15. Find the focal length â€˜fâ€™.
- How do you appreciate the coincidence of the experimental facts with the results obtained by a ray diagram in terms of behaviour of images formed by lenses?
- Suppose you are inside the water in a swimming pool near an edge. A friend is standing on the edge. Do you find your friend taller or shorter than his usual height? Why?
- Find the refractive index of the glass which is a symmetrical converging lens if its focal length is equal to the radius of curvature of its surface.
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