# Escape Speed Formula

## Escape Speed

Velocity or Escape speed is the speed of a body at which the total of the kinetic energy and gravitational potential energy is zero. The escape velocity from earth’s surface is about 11,186 m/s. In a different sense, it can be described as the speed required to break the gravitational attraction. The formula for escape speed is articulated as,

$v_{e}=\sqrt{\frac{2GM}{r}}$

Where,

G is the gravitational constant

is the mass of the planet

is the distance from the centre of gravity.

### Solved Example

Example 1: The mass of the Jupiter is given as 1.898×1027Kg and the radius is given as 71492km. Compute the escape speed?

Known parameters are,

Mass of the Jupiter, M = 1.898×1027kg

$v_{e}=\sqrt{\frac{2GM}{r}}$
$v_{e}=\sqrt{\frac{2\times 6.673\times 10^{-11}\times 1.898\times 10^{27}}{71492}}=188.23km/s$