Frank Solutions for Class 9 Maths Chapter 2 Profit, Loss and Discount provide students with a clear knowledge of the important concepts discussed in this chapter. The solutions are helpful in enhancing problem solving and logical thinking abilities among students. They are suggested to practise these solutions on a daily basis to speed up their exam preparation. Here, students can make use of Frank Solutions for Class 9 Maths Chapter 2 Profit, Loss and Discount PDF, from the links which are mentioned below.
Chapter 2 has important concepts of Profit, Loss and Discount and the steps used in determining them are explained in brief under this chapter. The solutions are provided in a descriptive manner to make learning fun for the students. After working on the chapter wise problems from the textbook, students can follow these solutions to understand the various methods, which can be used in solving the problems quickly.
Frank Solutions for Class 9 Maths Chapter 2 Profit, Loss and Discount Download PDF
Access Frank Solutions for Class 9 Maths Chapter 2 Profit, Loss and Discount
1. Find the loss percentage incurred by selling a watch for Rs 1610 that was purchased for Rs 1750
Solution:
Given
C.P of the watch = Rs 1750
S.P of the watch = Rs 1610
Loss = C.P – S.P
= Rs (1750 – 1610)
= Rs 140
Loss% = (Loss / C.P) × 100
= (140 / 1750) × 100
We get,
= 8%
Therefore, the loss percentage is 8%
2. Find the selling price of a camera bought for Rs 4600 and sold at a profit of 15%
Solution:
Given
C.P of the camera = Rs 4600
Profit = 15%
(S.P / C.P) = 1 + Profit / 100
(S.P / 4600) = 1 + 15 / 100
(S.P. / 4600) = (100 + 15) / 100
S.P = (115 / 100) × 4600
= Rs 5290
Therefore, the selling price of a camera is Rs 5290
3. Find the selling price of a watch bought for Rs 4050 and sold at a loss of 14%
Solution:
Given
C.P of the watch = Rs 4050
Loss = 14%
(S.P / C.P) = 1 – Loss / 100
S.P / 4050 = 1 – 14 / 100
S.P / 4050 = (100 – 14) / 100
S.P = (86 / 100) × 4050
We get,
S.P = Rs 3483
Therefore, the selling price of a watch is Rs 3483
4. A man buys a car for Rs 75000 and spends Rs 15000 on repairing it. If he sells the car now for Rs 114000, find the gain per cent.
Solution:
Given
C.P of the car = Rs 75000
Money spent on repairing = Rs 15000
Total C.P = Rs 75000 + Rs 15000
= Rs 90000
S.P of the car = Rs 114000
Gain = S.P – C.P
= Rs (114000 – 90000)
= Rs 24000
Gain% = (Gain / C.P) × 100
= (24000 / 90000) × 100
We get,
= 26.6%
Therefore, the gain percent of the car is 26.6%
5. A shopkeeper expects a profit of 25% on his cost price. In a week, his sale was of Rs 5000 what was his profit?
Solution:
Let the cost price = Rs 100
So, the profit will be Rs {(25 / 100) × 100}
= Rs 25
SP = CP + Profit
SP = Rs (100 + 25)
SP = Rs 125
Thus,
When the profit is Rs 25, the sale is Rs 125
Let x be the profit when the sale is Rs 5000
x = (25 × 5000) / 125
x = Rs 1000
Therefore, the profit is Rs 1000
6. On selling 10 watches at Rs 1400 there is a loss equal to the cost price of 3 watches. Find the cost price of a watch.
Solution:
Let the CP of 3 watches be Rs x
Hence,
CP of 1 watch = Rs (x / 3)
CP of 10 watches = Rs (10x / 3)
Loss on selling 10 watches = CP of 3 watches = Rs x
SP of 10 watches = Rs 1400
Loss incurred on selling 10 watches = CP of 3 watches = Rs x
Since CP – SP = Loss
Rs (10x / 3) – Rs 1400 = Rs x
(10x – 4200) / 3 = x
10x – 4200 = 3x
7x = 4200
We get,
x = 600
Therefore,
CP of a watch = Rs (x / 3)
CP of a watch = Rs (600 / 3) = Rs 200
7. Anant bought toffees at 5 for a rupee. How many for a rupee must he sell to gain 25%?
Solution:
CP of 5 toffees = Rs 1
SP of 5 toffees = {(100 + Profit%) / 100} of CP
= {(100 + 25) / 100} × Rs 1
= 125% × Rs 1
We get,
= Rs (5 / 4)
For Rs (5 / 4), toffees sold = 5
For Rs 1, toffees sold = (5 × 4 / 5) = 4
Therefore,
4 toffees were sold to gain 25%
8. By selling a tie for Rs 6.48, a shopkeeper gains 8%. At what price should he sell the tie to gain 10%?
Solution:
The S.P of a tie = Rs 648
Gain = 8%
(S.P.) / C.P.) = 1 + (Profit / 100)
(648 / C.P.) = 1 + (8 / 100)
648 / C.P. = {(100 + 8) / 100}
C.P = (100 / 108) × 648
C.P. = Rs 600
Now,
C.P. of the tie = Rs 600
Gain = 10%
Hence,
Gain = (10 / 100) × C.P.
= (10 / 100) × 600
We get,
= Rs 60
Therefore,
S.P. = Rs (600 + 60)
= Rs 660
Therefore, the shopkeeper must sell the tie at Rs 660 to make a gain of 10%
9. Find the SP in the following:
(a) MP = Rs 850, Discount = 16%
(b) MP = Rs 5500, Discount = 30%
Solution:
(a) MP = Rs 850
Discount = 16%
Discount% = {(discount / MP) × 100}
16 = {(discount / 850) × 100}
We get,
Discount = (16 × 850) / 100
We get,
Discount = Rs 136
S.P. = MP – discount
= Rs 850 – Rs 136
= Rs 714
Therefore, the S.P. is Rs 714
(b) MP = Rs 5500, Discount = 30%
Discount% = (discount / MP) × 100
30 = (discount / 5500) × 100
Discount = (30 × 5500) / 100
We get,
Discount = Rs 1650
S.P. = MP – Discount
= Rs 5500 – Rs 1650
= Rs 3850
Therefore, the S.P. is Rs 3850
10. Find the MP in the following:
(a) S.P. = Rs 1892, Discount = 14%
(b) S.P. = Rs 1245, Discount = 17%
Solution:
(a) SP = Rs 1892
Discount = 14%
SP = (1 – d / 100) of MP
1892 = (1 – 14 / 100) × MP
1892 = (86 / 100) × MP
MP = (1892 × 100) / 86
We get,
MP = Rs 2200
(b) SP = Rs 1245
Discount = 17%
SP = (1 – d / 100) of MP
1245 = (1 – 17 / 100) × MP
1245 = (83 / 100) × MP
MP = (1245 × 100) / 83
We get,
MP = Rs 1500
11. Find the discount percentage in the following:
(a) MP = Rs 1500, SP = Rs 1320
(b) MP = Rs 6840, SP = Rs 5814
Solution:
(a) MP = Rs 1500
SP = Rs 1320
Discount = MP – SP
Discount = Rs 1500 – Rs 1320
Discount = Rs 180
Discount percentage = {(discount / MP) × 100}%
= {(180 / 1500) × 100}%
We get,
= 12%
(b) MP = Rs 6840
SP = Rs 5814
Discount = MP – SP
Discount = Rs 6840 – Rs 5814
Discount = Rs 1026
Discount percentage = {(1026 / 6840) × 100}%
We get,
Discount percentage = 15%
12. Find the amount paid by a customer when he buys a watch priced at Rs 5400 available at a discount of 12%
Solution:
MP = Rs 5400
Discount = 12%
To find the amount paid by the customer,
i.e, SP
SP = (1 – d / 100) of MP
SP = (1 – 12 / 100) × 5400
SP = (88 / 100) × 5400
We get,
SP = Rs 4752
Therefore, the amount paid by the customer is Rs 4752
13. Find the S.P. in the following:
(i) M.P = Rs 850, Discount = 16%
(ii) M.P = Rs 5500, Discount = 30%
(iii) M.P = Rs 1625, Discount = 12%
Solution:
(i) M.P = Rs 850
Discount = 16%
(SP / MP) = 1 – (discount / 100)
SP / 850 = 1 – (16 / 100)
SP = (84 / 100) × 850
We get,
= Rs 714
(ii) M.P = Rs 5500
Discount = 30%
(SP / MP) = 1 – (discount / 100)
SP / 5500 = 1 – (30 / 100)
SP = (70 / 100) × Rs 5500
We get,
= Rs 3850
(iii) M.P = Rs 1625
Discount = 12%
(SP / MP) = 1 – (discount / 100)
SP / 1625 = 1 – (12 / 100)
S.P = (88 / 100) × 1625
We get,
= Rs 1430
14. Find the M.P in the following:
(i) S.P = Rs 1892, Discount = 14%
(ii) S.P = Rs 1245, Discount = 17%
(iii) S.P = Rs 5343, Discount = 22%
Solution:
(i) S.P = Rs 1892
Discount = 14%
(SP / MP) = 1 – (discount / 100)
1892 / MP = 1 – (14 / 100)
MP = (100 / 86) × 1892
We get,
MP = Rs 2200
(ii) S.P = Rs 1245
Discount = 17%
(SP / MP) = 1 – (discount / 100)
1245 / MP = 1 – (17 / 100)
MP = (100 / 83) × 1245
We get,
MP = Rs 1500
(iii) S.P = Rs 5343
Discount = 22%
(SP / MP) = 1 – (discount / 100)
5343 / MP = 1 – (22 / 100)
MP = (100 / 78) × 5343
We get,
MP = Rs 6850
15. Find the discount percentage in the following:
(i) M.P = Rs 1500, S.P = Rs 1320
(ii) M.P = Rs 6840, S.P = Rs 5814
(iii) M.P = Rs 1960, S.P = Rs 1176
Solutions:
(i) M.P = Rs 1500
S.P = Rs 1320
(S.P / MP) = 1 – (discount / 100)
1320 / 1500 = 1 – (D / 100)
D / 100 = 1 – (1320 / 1500)
On further calculation, we get,
D = (180 / 1500) × 100
We get,
D = 12
Therefore, discount = 12%
(ii) MP = Rs 6840
SP = Rs 5814
(SP / MP) = 1 – (discount / 100)
5814 / 6840 = 1 – (D / 100)
D / 100 = 1 – (5814 / 6840)
On further calculation, we get,
D = (1026 / 6840) × 100
We get,
D = 15
Therefore, discount = 15%
(iii) MP = Rs 1960
SP = Rs 1176
(SP / MP) = 1 – (discount / 100)
1176 / 1960 = 1 – (D / 100)
D / 100 = 1 – (1176 / 1960)
On further calculation, we get,
D = (784 / 1960) × 100
We get,
D = 40
Therefore, discount = 40%
