Heat gain or loss results to changes in temperature, state and performance of the work. Heat is a transfer of energy. The heat capacity of a defined object is usually expressed in joules or calories and temperature in Kelvin or Celsius.
Heat Capacity formula is expressed by,
ΔQ = amount of heat transferred,
ΔT = temperature difference.
Heat Capacity problem can be applied to calculate the heat capacity, mass or temperature difference of any given substance.
Heat Capacity is described in Joule per Kelvin (J/K).
Please note that in Heat capacity, we consider the specific amount of mass and that mass can be any amount.
Determine the heat capacity of copper of mass 70 g and the temperature difference is 20oC if 300 J of heat is lost.
Given parameters are,
Mass m = 70 g,
Temperature difference T = 20oC,
Heat lost Δ Q = 300 J
the Heat capacity formula is given by
c = ΔQ / ΔT
c= 300 / 20
c= 15 J/oC
Determine the heat capacity of 3000 J of heat is used to heat the iron rod of mass 10 Kg from 20oC to 40oC.
Given parameters are
Mass m = 10 Kg,
Temperature difference Δ T = 20oC,
Heat lost ΔQ = 3000 J
The Heat capacity formula is given by
c = ΔQ / ΔT
c= 3000 / 20
c= 150 J/oC