Selina Solutions Concise Mathematics Class 6 Chapter 14: Fractions Exercise 14(D)

Selina Solutions Concise Mathematics Class 6 Chapter 14 Fractions Exercise 14(D) has clear answers for each and every question based on the concept BODMAS. The examples before each exercise of Selina textbook help them to achieve more marks in the final examination. Students, who aspire to strengthen their skill in Mathematics, are advised to follow Selina Solutions and hence, practice regularly. These Solutions also help them in solving difficult questions effortlessly. Students can use Selina Solutions Concise Mathematics Class 6 Chapter 14 Fractions Exercise 14(D) PDF, from the links provided here for free download.

Selina Solutions Concise Mathematics Class 6 Chapter 14: Fractions Exercise 14(D) Download PDF

selina solution concise maths class 6 chapter 14 ex d 1
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Access other exercises of Selina Solutions Concise Mathematics Class 6 Chapter 14: Fractions

Exercise 14(A) Solutions

Exercise 14(B) Solutions

Exercise 14(C) Solutions

Exercise 14(E) Solutions

Access Selina Solutions Concise Mathematics Class 6 Chapter 14: Fractions Exercise 14(D)

Exercise 14(D)

1. Simplify:

(i) 3 / 7 × 2 / 5

(ii) 4 / 9 × 3 / 5

(iii) 5 / 12 × 8

(iv) 7 / 6 of 3 / 14

(v) Selina Solutions Concise Mathematics Class 6 Chapter 14 - 82 × Selina Solutions Concise Mathematics Class 6 Chapter 14 - 83

Solution:

(i) 3 / 7 × 2 / 5

The given expression can be simplified as below

3 / 7 × 2 / 5 = (3 × 2) / (7 × 5)

= 6 / 35

Hence, the simplified form of the given expression is 6 / 35

(ii) 4 / 9 × 3 / 5

The given expression can be simplified as below

4 / 9 × 3 / 5 = (4 × 3) / (9 × 5)

= (4 × 1) / (3 × 5)

= 4 / 15

Hence, the simplified form of the given expression is 4 / 15

(iii) 5 / 12 × 8

The given expression can be simplified as below

5 / 12 × 8 / 1 = (5 × 8) / (12 × 1)

= (5 × 2) / (3 × 1)

= 10 / 3

=
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 84

Hence, the simplified form of the given expression is
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 85

(iv) 7 / 6 of 3 / 14

The given expression can be simplified as below

7 / 6 × 3 / 14 = (1 × 1) / (2 × 2)

= 1 / 4

Hence, the simplified form of the given expression is 1 / 4

(v)
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 86×
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 87

The given expression can be simplified as below

Selina Solutions Concise Mathematics Class 6 Chapter 14 - 88×
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 89= (27 × 27) / (8 × 7)

= 729 / 56

=
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 90

Hence, the simplified form of the given expression is
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 91

2. Simplify:

(i) 2 / 3 ÷ Selina Solutions Concise Mathematics Class 6 Chapter 14 - 92

(ii) Selina Solutions Concise Mathematics Class 6 Chapter 14 - 93 ÷ 4 / 9

(iii) 1 ÷ 2 / 5

(iv) 4 / 9 ÷ 4 / 9

(v) Selina Solutions Concise Mathematics Class 6 Chapter 14 - 94 ÷ Selina Solutions Concise Mathematics Class 6 Chapter 14 - 95

Solution:

(i) 2 / 3 ÷
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 96

The given expression can be simplified as below

2 / 3 ÷ 6 / 5 = (2 × 5) / (3 × 6)

= 5 / 9

Hence, the simplified form of the given expression is 5 / 9

(ii)
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 97÷ 4 / 9

The given expression can be simplified as below

9 / 2 ÷ 4 / 9 = (9 × 9) / (2 × 4)

= 81 / 8

=
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 98

Hence, the simplified form of the given expression is
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 99

(iii) 1 ÷ 2 / 5

The given expression can be simplified as below

1 / 1 ÷ 2 / 5 = (1 × 5) / (1 × 2)

= 5 / 2

=
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 100

Hence, the simplified form of the given expression is
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 101

(iv) 4 / 9 ÷ 4 / 9

The given expression can be simplified as below

4 / 9 ÷ 4 / 9 = (4 × 9) / (9 × 4)

=1

Hence, the simplified form of the given expression is 1

(v)
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 102÷
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 103

The given expression can be simplified as below

Selina Solutions Concise Mathematics Class 6 Chapter 14 - 104÷
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 105= (7 × 4) / (3 × 7)

= 4 / 3

=
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 106

Hence, the simplified form of the given expression is
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 107

3. Simplify:

(i) 1 / 4 of Selina Solutions Concise Mathematics Class 6 Chapter 14 - 108 ÷ 3 / 5

(ii) Selina Solutions Concise Mathematics Class 6 Chapter 14 - 109 × 1 / 2 ÷ Selina Solutions Concise Mathematics Class 6 Chapter 14 - 110

(iii) Selina Solutions Concise Mathematics Class 6 Chapter 14 - 111 × 0 × Selina Solutions Concise Mathematics Class 6 Chapter 14 - 112

(iv) 3 / 4 × Selina Solutions Concise Mathematics Class 6 Chapter 14 - 113 ÷ 3 / 7 of Selina Solutions Concise Mathematics Class 6 Chapter 14 - 114

(v) Selina Solutions Concise Mathematics Class 6 Chapter 14 - 115 ÷ 2 / 7 of Selina Solutions Concise Mathematics Class 6 Chapter 14 - 116 × 2 / 3

Solution:

(i) 1 / 4 of
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 117÷ 3 / 5

The given expression can be simplified as follows:

1 / 4 × 16 / 7 ÷ 3 / 5 = 4 / 7 ÷ 3 / 5

= (4 × 5) / (7 × 3)

= 20 / 21

Hence, 20 / 21 is the simplified form of the given expression

(ii) Selina Solutions Concise Mathematics Class 6 Chapter 14 - 118 × 1 / 2 ÷
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 119

The given expression can be simplified as follows

Selina Solutions Concise Mathematics Class 6 Chapter 14 - 120× 1 / 2 ÷
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 121= 5 / 4 × 1 / 2 × 3 / 4

= 5 / 8 × 3 / 4

= 15 / 32

Hence, 15 / 32 is the simplified form of the given expression

(iii)
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 122× 0 × Selina Solutions Concise Mathematics Class 6 Chapter 14 - 123

The given expression can be simplified as follows

Selina Solutions Concise Mathematics Class 6 Chapter 14 - 124× 0 × Selina Solutions Concise Mathematics Class 6 Chapter 14 - 125 = (43 × 0 × 43) / (7 × 0 × 8)

= 0

Hence, 0 is the simplified form of the given expression

(iv) 3 / 4 ×
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 126÷ 3 / 7 of
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 127

The given expression can be simplified as follows

3 / 4 ×
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 128÷ 3 / 7 of
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 129= 3 / 4 × 4 / 3 ÷ 9 / 8

∵ 3 / 7 of
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 130= 3 / 7 × 21 / 8 = 9 / 8

= 3 / 4 × 4 / 3 × 8 / 9

= 8 / 9

Hence, 8 / 9 is the simplified form of the given expression

(v)
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 131÷ 2 / 7 of
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 132× 2 / 3

The given expression can be simplified as follows

[2 / 7 of
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 133= 2 / 7 × 4 / 3 = 8 / 21]

We get

= 9 / 4 ÷ 8 / 21 × 2 / 3

= 9 / 4 × 21 / 8 × 2 / 3

= 63 / 16

=
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 134

Hence,
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 135is the simplified form of the given expression

4. Simplify:

(i) 5 – (8 / 11 – Selina Solutions Concise Mathematics Class 6 Chapter 14 - 136)

(ii) 1 / 2 ÷ (7 / 8 – 3 / 5)

(iii) Selina Solutions Concise Mathematics Class 6 Chapter 14 - 137 ÷ (Selina Solutions Concise Mathematics Class 6 Chapter 14 - 138 + Selina Solutions Concise Mathematics Class 6 Chapter 14 - 139)

(iv) (Selina Solutions Concise Mathematics Class 6 Chapter 14 - 140
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 141) ÷ 1 / 2

(v) 4 / 7 ÷ (1 / 3 ×
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 142)

Solution:

(i) 5 – (8 / 11Selina Solutions Concise Mathematics Class 6 Chapter 14 - 143)

The given expression can be simplified as below

5 – (8 / 11 –
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 144) = 5 – (8 / 11 – 36 / 11)

= 5 – (8 – 36) / 11

= 5 – (-28 / 11)

On further calculation, we get

= 5 / 1 + 28 / 11

= 83 / 11

=
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 145

Hence,
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 146is the simplified form of the given expression

(ii) 1 / 2 ÷ (7 / 8 – 3 / 5)

The given expression can be simplified as below

1 / 2 ÷ (7 / 8 – 3 / 5) = 1 / 2 ÷ (5 × 7 – 8 × 3) / 40

= 1 / 2 ÷ (35 – 24) / 40

= 1 / 2 ÷ (11 / 40)

= 1 / 2 × 40 / 11

We get

= 20 / 11

=
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 147

Hence,
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 148is the simplified form of the given expression

(iii)
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 149 ÷ (Selina Solutions Concise Mathematics Class 6 Chapter 14 - 150 + Selina Solutions Concise Mathematics Class 6 Chapter 14 - 151)

The given expression can be simplified as below

Selina Solutions Concise Mathematics Class 6 Chapter 14 - 152 ÷ (Selina Solutions Concise Mathematics Class 6 Chapter 14 - 153 + Selina Solutions Concise Mathematics Class 6 Chapter 14 - 154) = 7 / 3 ÷ (11 / 2 + 15 / 4)

= 7 / 3 ÷ (2 × 11 + 1 × 15) / 4

On further calculation, we get

= 7 / 3 ÷ (22 + 15) / 4

= 7 / 3 ÷ (37 / 4)

= 7 / 3 × 4 / 37

= 28 / 111

Hence, 28 / 111 is the simplified form of the given expression

(iv) (Selina Solutions Concise Mathematics Class 6 Chapter 14 - 155
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 156) ÷ 1 / 2

The given expression can be simplified as below

(Selina Solutions Concise Mathematics Class 6 Chapter 14 - 157
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 158) ÷ 1 / 2 = (31 / 8 – 18 / 5) ÷ 1 / 2

By taking LCM, we get

= [(31 × 5 – 18 × 8) / (8 × 5)] ÷ 1 / 2

= (155 – 144) / 40 ÷ 1 / 2

= (11 / 40) ÷ 1 / 2

By calculating further, we get

= 11 / 40 × 2 / 1

= 11 / 20

Hence, 11 / 20 is the simplified form of the given expression

(v) 4 / 7 ÷ (1 / 3 ×
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 159)

The given expression can be simplified as below

4 / 7 ÷ (1 / 3 ×
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 160) = 4 / 7 ÷ (1 / 3 × 14 / 5)

= 4 / 7 ÷ (14 / 15)

On further calculation, we get

= 4 / 7 × 15 / 14

= 2 / 7 × 15 / 7

= 30 / 49

Hence, 30 / 49 is the simplified form of the given expression

5. Simplify

(i) (1 / 2 + 1 / 3) ÷ (1 / 4 – 1 / 6)

(ii) (24 / 35 ÷ 6 / 7 + 5 / 9) × 3 / 4

(iii) 3 / 4 of Selina Solutions Concise Mathematics Class 6 Chapter 14 - 161 – 2 / 3 of Selina Solutions Concise Mathematics Class 6 Chapter 14 - 162

(iv) 7 / 30 of (1 / 3 + 7 / 15) ÷ (5 / 6 – 3 / 5)

(v) Selina Solutions Concise Mathematics Class 6 Chapter 14 - 163Selina Solutions Concise Mathematics Class 6 Chapter 14 - 164 × Selina Solutions Concise Mathematics Class 6 Chapter 14 - 165 + Selina Solutions Concise Mathematics Class 6 Chapter 14 - 166

Solution:

(i) (1 / 2 + 1 / 3) ÷ (1 / 4 – 1 / 6)

The given expression can be simplified as follows

(1 / 2 + 1 / 3) ÷ (1 / 4 – 1 / 6) = [(3 + 2) / 6] ÷ [(3 – 2) / 12]

On further calculation, we get

= (5 / 6) ÷ (1 / 12)

= 5 / 6 × 12 / 1

= 5 × 2

= 10

Hence, the simplified form of the given expression is 10

(ii) (24 / 35 ÷ 6 / 7 + 5 / 9) × 3 / 4

The given expression can be simplified as follows

(24 / 35 ÷ 6 / 7 + 5 / 9) × 3 / 4 = (24 / 35 × 7 / 6 + 5 / 9) × 3 / 4

= (4 / 5 + 5 / 9) × 3 / 4

By taking LCM, we get

= [(36 + 25) / 45] × 3 / 4

= (61 / 45) × 3 / 4

We get

= 61 / 60

=
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 167

Hence, the simplified form of the given expression is
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 168

(iii) 3 / 4 of
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 169– 2 / 3 of
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 170

The given expression can be simplified as below

3 / 4 of
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 171– 2 / 3 of
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 172= 3 / 4 of 49 / 8 – 2 / 3 of 9 / 4

= 3 / 4 × 49 / 8 – 2 / 3 of 9 / 4

= 147 / 32 – 2 / 3 × 9 / 4

We get

= 147 / 32 – 3 / 2

On taking LCM, we get

= [(147 – 48)] / 32

= 99 / 32

=
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 173

Hence, the simplified form of the given expression is
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 174

(iv) 7 / 30 of (1 / 3 + 7 / 15) ÷ (5 / 6 – 3 / 5)

The given expression can be simplified as below

7 / 30 of (1 / 3 + 7 / 15) ÷ (5 / 6 – 3 / 5) = 7 / 30 of [(5 + 7) / 15] ÷ [(25 – 18) / 30]

We get

= 7 / 30 of (4 / 5) ÷ (7 / 30)

= 7 / 30 × 4 / 5 × 30 / 7

= 4 / 5

Hence, the simplified form of the given expression is 4 / 5

(v)
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 175 Selina Solutions Concise Mathematics Class 6 Chapter 14 - 176 × Selina Solutions Concise Mathematics Class 6 Chapter 14 - 177 + Selina Solutions Concise Mathematics Class 6 Chapter 14 - 178

The given expression can be simplified as below

Selina Solutions Concise Mathematics Class 6 Chapter 14 - 179
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 180×
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 181+
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 182= 5 / 2 – 7 / 2 × 7 / 4 + 5 / 2

= 5 / 2 – 49 / 8 + 5 / 2

= 5 / 2 + 5 / 2 – 49 / 8

By taking LCM, we get

= (20 + 20 – 49) / 8

= (40 – 49) / 8

= – 9 / 8

= –
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 183

Hence, –
Selina Solutions Concise Mathematics Class 6 Chapter 14 - 184is the simplified form of the given expression

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