# Selina Solutions Concise Maths Class 7 Chapter 11: Fundamental Concepts (Including Fundamental Operations) Exercise 11A

Selina Solutions Concise Maths Class 7 Chapter 11 Fundamental Concepts (Including Fundamental Operations) Exercise 11A provides students with a clear picture of the basic terms, which are important from the exam perspective. The solutions contain concepts explained in a simple language to help students perform well in the annual exam. The expert faculty at BYJUâ€™S design the solutions after conducting vast research on each concept. Students can refer to Selina Solutions Concise Maths Class 7 Chapter 11 Fundamental Concepts (Including Fundamental Operations) Exercise 11A PDF, from the links provided here.

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#### Exercise 11A page: 121

1. Separate constant terms and variable terms from the following:

8, x, 6xy, 6 + x, – 5xy2, 15az2, 32z/ xy, y2/ 3x

Solution:

The constant term is 8.

The variable terms are x, 6xy, 6 + x, – 5xy2, 15az2, 32z/ xy, y2/ 3x.

2. For each expression, given below, state whether it is a monomial, binomial or trinomial:

(i) 2x Ã· 15

(ii) ax + 9

(iii) 3x2 Ã— 5x

(iv) 5 + 2x â€“ 3b

(v) 2y â€“ 7z/3 Ã· x

(vi) 3p Ã— q Ã· z

(vii) 12z Ã· 5x + 4

(viii) 12 â€“ 5z â€“ 4

(ix) a3 -3ab2 Ã— c

Solution:

(i) 2x Ã· 15 = 2x/15

It has one term and hence it is a monomial.

(ii) ax + 9

It has two terms and hence it is a binomial.

(iii) 3x2 Ã— 5x = 15x3

It has one term and hence it is a monomial.

(iv) 5 + 2x â€“ 3b

It has three terms and hence it is a trinomial.

(v) 2y â€“ 7z/3 Ã· x = 2y â€“ 7z/3x

It has two terms and hence it is a binomial.

(vi) 3p Ã— q Ã· z = 3pq/z

It has one term and hence it is a monomial.

(vii) 12z Ã· 5x + 4 = 12z/5x + 4

It has two terms and hence it is a binomial.

(viii) 12 â€“ 5z â€“ 4 = 8 â€“ 5z

It has two terms and hence it is a binomial.

(ix) a3 -3ab2 Ã— c = a3 â€“ 3ab2c

It has two terms and hence it is a binomial.

3. Write the coefficient of:

(i) xy in -3axy

(ii) z2 in p2yz2

(iii) mn in â€“ mn

(iv) 15 in -15p2

Solution:

(i) xy in -3axy

The coefficient of xy in -3axy = -3a

(ii) z2 in p2yz2

The coefficient of z2 in p2yz2 = p2y

(iii) mn in â€“ mn

The coefficient of mn in â€“ mn = -1

(iv) 15 in -15p2

The coefficient of 15 in -15p2 = -p2

4. For each of the following monomials, write its degree:

(i) 7y

(ii) â€“x2y

(iii) xy2z

(iv) -9y2z3

(v) 3m3n4

(vi) -2p2q3r4

Solution:

(i) The degree of 7y is 1.

(ii) The degree of â€“x2y = 2 + 1 = 3

(iii) The degree of xy2z = 1 + 2 + 1 = 4

(iv) The degree of -9y2z3 = 2 + 3 = 5

(v) The degree of 3m3n4 = 3 + 4 = 7

(vi) The degree of -2p2q3r4 = 2 + 3 + 4 = 9

5. Write the degree of each of the following polynomials:

(i) 3y3 â€“ x2y2 + 4x

(ii) p3q2 â€“ 6p2q5 + p4q4

(iii) -8mn6 + 5m3n

(iv) 7 â€“ 3x2y + y2

(v) 3x â€“ 15

(vi) 2y2z + 9yz3

Solution:

(i) The degree of 3y3 â€“ x2y2 + 4x is 4

x2y2 is the term which has the highest degree.

(ii) The degree of p3q2 â€“ 6p2q5 + p4q4 is 8

p4q4 is the term which has the highest degree.

(iii) The degree of -8mn6 + 5m3n is 7

-8mn6 is the term which has the highest degree.

(iv) The degree of 7 â€“ 3x2y + y2 is 3

â€“ 3x2y is the term which has the highest degree.

(v) The degree of 3x â€“ 15 is 1

3x is the term which has the highest degree.

(vi) The degree of 2y2z + 9yz3 is 4

9yz3 is the term which has the highest degree.

6. Group the like terms together:

(i) 9x2, xy, -3x2, x2 and -2xy

(ii) ab, -a2b, -3ab, 5a2b and -8a2b.

(iii) 7p, 8pq, -5pq, -2p and 3p

Solution:

(i) 9x2, xy, -3x2, x2 and -2xy

9x2, -3x2 and x2 are like terms

xy and -2xy are like terms.

(ii) ab, -a2b, -3ab, 5a2b and -8a2b

-a2b, 5a2b and -8a2b are like terms

ab and â€“ 3ab are like terms.

(iii) 7p, 8pq, -5pq, -2p and 3p

7p, -2p and 3p are like terms

8pq and -5pq are like terms.

7. Write the numerical coefficient of each of the following:

(i) y

(ii) â€“ y

(iii) 2x2y

(iv) -8xy3

(v) 3py2

(vi) -9a2b3

Solution:

(i) The numerical coefficient of y is 1.

(ii) The numerical coefficient of â€“ y is â€“ 1.

(iii) The numerical coefficient of 2x2y is 2.

(iv) The numerical coefficient of -8xy3 is -8.

(v) The numerical coefficient of 3py2 is 3.

(vi) The numerical coefficient of -9a2b3 is -9.

8. In -5x3y2z4; write the coefficient of:

(i) z2

(ii) y2

(iii) yz2

(iv) x3y

(v) â€“xy2

(vi) -5xy2z

Also, write the degree of the given algebraic expression.

Solution:

(i) The coefficient of z2 is -5x3y2z2.

(ii) The coefficient of y2 is -5x3z4.

(iii) The coefficient of yz2 is -5x3yz2.

(iv) The coefficient of x3y is -5yz4.

(v) The coefficient of â€“xy2 is 5x2z4.

(vi) The coefficient of -5xy2z is x2z3.

So the degree of the given algebraic expression = 3 + 2 + 4 = 9.