JEE Main 2017 results were announced today by the Central Board of Secondary Education (CBSE) as the cut-off scores are low as unexpected this year. For the general category, the cut-off score is 81 which had dented the hopes of the expected cut- off score to be between 95 -105 this year. To be eligible for the JEE Advanced from the common rank list, aspirants numbering to above one lakh would be able to do so. The exam was conducted on 2nd, 8th, and 9th April this year. The score of the exam this year would not be determined on the basis of class XII exam marks. The eligibility for the advanced level would be determined based on the mains exam score and rank.
The cut-off scores for the last year for SC, ST and OBC 52, 48 and 70 and 100 for general category.
For the mains exam, around 10.20 lakh students attended this year. To appear for the advanced exam, around 2.20 lakh top scorers would get the chance for the same. The qualified aspirants would have to register for the advanced level anytime from now onwards. The Indian Institute of Technology (IIT), Madras will conduct the advanced level exam on 21st May 2017.
Students who have scored above 75 per cent in their class XII board exams will be eligible to attend the Advanced exam (65 per cent for SC and ST students).
Calculation Of The Scores
Furthermore, students will also be able to calculate their score based on the percentage of their percentile. Percentile is calculated using the aggregate marks of the five subjects to find the board position of the candidate. The normalized score is calculated using the percentile. Students from the general category have to score around 50.5 per cent whereas OBC, SC and ST have to score 21, 15 and 7.5 per cent respectively to appear for the advanced exam.
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