An ellipse is a curve in the plane which surrounds the two focal points such that the distances to the focal point remain constant for each point on the curve. A circle is said to be a special type of ellipse having both focal points at the same point. A line which intersects the ellipse at a point is called a tangent to the ellipse. The different forms of the tangent equation are given below:
- Slope form of a tangent to an ellipse
If the line y = mx + c touches the ellipse x2 / a2 + y2 / b2 = 1, then c2 = a2m2 + b2. The straight line y = mx ∓ √[a2m2 + b2] represents the tangents to the ellipse.
- Point form of a tangent to an ellipse
The equation of the tangent to an ellipse x2 / a2 + y2 / b2 = 1 at the point (x1, y1) is xx1 / a2 + yy1 / b2 = 1.
- The parametric form of a tangent to an ellipse
The equation of the tangent at any point (a cosɸ, b sinɸ) is [x / a] cosɸ + [y / b] sinɸ.
- Point of contact of the tangent to an ellipse
Line y = mx ∓ √[a2m2 + b2] touches the ellipse x2 / a2 + y2 / b2 = 1 at (∓a2m / √[a2m2 + b2]) , (∓b2 / √[a2m2 + b2]).
Equation of Tangent to Ellipse Problems
Example 1: What is the locus of the point of intersection of perpendicular tangents to the ellipse x2 / a2 + y2 / b2 = 1?
Solution:
Let the point be (h, k). The pair of tangents will be
(x2 / a2 + y2 / b2 − 1) (h2 / a2 + k2 / b2 − 1) = (hx / a2 +yk / b2 − 1)2
The pair of tangents will be perpendicular if coefficient of x2 + coefficient of y2 = 0
k2 / a2b2 + h2 / a2b2 = 1 / a2 + 1 / b2
h2 + k2 = a2 + b2
Replace (h, k) by (x, y)
x2 + y2 = a2 + b2.
Example 2: What is the condition for the line lx + my − n = 0 to be tangent to the ellipse x2 / a2 + y2 / b2 = 1?
Solution:
y = [−l / m] x + n / m is tangent to x2 / a2 + y2 / b2 = 1, if
n / m = ± √b2 + [a2 / (l / m)2] or
On simplification,
n2 = m2b2 + l2a2.
Example 3: If any tangent to the ellipse x2 / a2 + y2 / b2 = 1 cuts off intercepts of length h and k on the axes, then a2 / h2 + b2 / k2 = ___________.
Solution:
The tangent at (a cosθ, b sinθ) to the ellipse is [(a cos θ) * x] / [a2] +[b sin θ] * y / b2 = 1
or x / (a / cos θ) + y / (b / sin θ) = 1
∴Intercepts are, h = a / cos θ, k = b sin θ
a2 / h2 + b2 / k2 = 1
Example 4: The equation of the tangents drawn at the ends of the major axis of the ellipse 9x2 + 5y2 − 30y = 0, are ___________.
Solution:
Change the equation 9x2 + 5y2 − 30y = 0 in standard form 9x2 + 5 (y2 − 6y) = 0
9x2 + 5 (y2 − 6y + 9) = 45
x2 / 5 + (y − 3)2 / 9 = 1
∵ a2 < b2, so the axis of the ellipse is on the y-axis.
At the y-axis, put x = 0, so we can obtain the vertex.
Then, 0 + 5y2 − 30y = 0
y = 0, y = 6
Therefore, tangents of vertex y = 0, y = 6.
Example 5: The equation of tangent and normal at point (3, 2) of ellipse 4x2 + 9y2 = 36 are _________.
Solution:
Given, the equation of an ellipse is 4x2 + 9y2 = 36
The tangent at point (3, 2) is (3) * x / 9 + (−2) * y / 4 = 1 or x / 3 − y / 2 = 1
∴ Normal is x / 2 + y / 3 = k, and it passes through the point (3,2)
∴ 3 / 2 − 2 / 3 = k ⇒ k = 5 / 6
∴ Normal is, x / 2 + y / 3 = 5 / 6.
Example 6: Minimum area of the triangle by any tangent to the ellipse x2 / a2 + y2 / b2 = 1 with the coordinate axes is _____________.
Solution:
The equation of tangent at (a cos θ, b sin θ) is [x / a] cos θ + [y / b] sin θ = 1
P = (a / cos θ, 0)
Q = (0, b / sin θ)
Area of OPQ = 1 / 2 ∣(a / cos θ) (b / sin θ)∣ = ab / |sin 2θ|
(Area)min = ab
Example 7: The eccentric angles of the extremities of latus recta of the ellipse
Solution:
Coordinates of any point on the ellipse
whose eccentric angle is θ are (a cos θ, b sin θ).
Because
Thus, the answer is option C.
Example 8: The length of the axes of the conic
Solution:
Given that, the equation of the conic
Here
The length of the axes of the conic are 1, 2/3.
Thus, the answer is option C.
Example 9: The coordinates of the foci of the ellipse
A) (1, 2), (3, 4)
B) (1, 4), (3, 1)
C) (1, 1), (3, 1)
D) (2, 3), (5, 4)
Solution:
Foci are
Thus, the answer is option C.
Definitions of an Ellipse
Visualising Ellipses
Frequently Asked Questions
What do you mean by a tangent to an ellipse?
A tangent to an ellipse is a line that intersects the ellipse at one point.
Give the equation for the point form of a tangent to an ellipse.
The equation of the tangent to an ellipse (x2/a2) + (y2/b2) = 1 at the point (x1, y1) is given by (xx1/a2) + (yy1/b2) = 1.
What is the equation of normal to an ellipse?
The equation of the normal to the ellipse (x2/a2) + (y2/b2) = 1 at the point (x1, y1) is given by (a2x/x1) – (b2y/y1) = a2 – b2.
How many tangents can be drawn to an ellipse from an external point?
Two tangents can be drawn to an ellipse from an external point.
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