p-block – JEE Advanced Previous Year Questions with Solutions

p-Block Elements JEE Advanced Previous Year Questions with Solutions has been provided here to help JEE aspirants prepare well and score maximum marks in the JEE Advanced exam. Here aspirants and students likewise will find a set of questions that have appeared in the different sessions of the entrance exam in the past. In any case, this set of questions and solutions will play an important role in helping students and aspirants achieve their goal of succeeding in the exam.

As aspirants go through the questions and solutions they will further get familiar with the format of the question paper, its types and the difficulty level. Additionally, as they engage in constant practice to solve all the questions they will acquire adept problem-solving skills to tackle the different types of questions that could appear in the upcoming exam. Students or JEE aspirants can also download the p-Block Elements JEE Advanced Previous Year Questions with Solutions PDF directly from here.

Download p-Block Previous Year Solved Questions PDF

JEE Advanced Previous Year Questions on p-block

Question 1. The total number of compounds having at least one bridging oxo group among the molecules given below is:

N₂O₃, N₂O₅, P₄O₆, P₄O7, H₄P₂O₅, H₅P₃O10, H₂S₂O₃, H₂S₂O₅

Solution: (6)

Question 2. Based on the compounds of group 15 elements, the correct statement(s) is (are).

A. Bi₂O₅ is more basic than N₂O₅

B. NF₃ is more covalent than BiF₃

C. PH₃ boils at a lower temperature than NH₃

D. The N–N single bond is stronger than the P–P single bond

Solution: (A, B and C)

Bi₂O₅ is more basic than N₂O₅

As we go down the group, the metallic nature of the atom increases. Hence, the basic nature of its oxide increases. Hence, the given statement is true.

NF₃ is more covalent than BiF₃

As we go down the group, the metallic nature of the atom increases. Hence, the ionic character increases if we keep the anion constant. Thus, we can say that the given statement is true.

PH₃ boils at a lower temperature than NH₃

NH₃ has strong intermolecular hydrogen bonding which tends to increase its boiling point compared to PH₃. Hence, this statement is true.

N–N single bond is stronger than the P–P single bond

Since N is smaller in size, it faces lp-lp repulsion while forming N−N thereby reducing the effective overlap of the single bond. Thus, N−N is not stronger than P−P. Hence, the given statement is incorrect.

Question 3. The compound(s) which generate(s) N₂ gas upon thermal decomposition below 300°C is (are)

A. NH₄NO₃

B. (NH₄)₂Cr₂O₇

C. Ba(N₃)₂

D. Mg₃N₂

Solution: (B, C)

Question 4. The option(s) with only amphoteric oxides is (are):

A. Cr₂O₃, BeO, SnO, SnO₂

B. Cr₂O₃, CrO, SnO, PbO

C. NO, B₂O₃, PbO, SnO₂

D. ZnO, Al₂O₃, PbO, PbO₂

Solution: (A, D)

Amphoteric oxides are

ZnO, Al₂O₃, PbO, PbO₂, Cr₂O₃, BeO, SnO, SnO₂

NO is a neutral oxide.

CrO is a basic oxide.

B₂O₃ is an acidic oxide

Question 5. Among the following, the correct statement(s) is/are:

A. Al(CH₃)₃ has the three-centre two-electron bonds in its dimeric structure

B. Lewis acidity of BCl₃ is greater than that of AlCl₃

C. AlCl₃ has three-centre two-electron bonds in its dimeric structure

D. BH₃ has three-centre two-electron bonds in its dimeric structure

Solution: (A, B and D)

(A) Al(CH₃)₃ has the three – centre two-electron bonds in its dimeric structure. Structure of Al(CH₃)₆

(B) BCl₃ is a stronger Lewis acid due to the small size of boron.

(C) AlCl₃ has three-centre four-electron bonds in its dimeric structure. These bonds correspond to chlorine bridges between 2 Al atoms. Structure of AlCl₃

(D) BH₃ has three-centre two-electron bonds in its dimeric structure. Structure of BH₂H₆

Question 6. The increasing order of atomic radii of the following group 13 elements is.

A. Al < Ga < In < Tl

B. Ga < Al < In < Tl

C. Al < In < Ga < Tl

D. Al < Ga < Tl < In

Solution: (B)

The increasing order of atomic radius of group 13 elements is Ga < Al < In < Tl.

Due to the poor shielding of the d-orbital in Ga, its radius is smaller than that of Al.

Question 7. The total number of lone pairs of electrons in N₂O₃ is:

A. 2

B. 4

C. 8

D. 10

Solution: (C)

The total number of lone pairs of electrons in N₂O₃ is 8.

∴ Total number of lone pairs = 2 + 1 + 3 + 2 = 8.

Question 8. The product formed in the reaction of SOCl₂with white phosphorous is:

A. PCl₃

B. So₂Cl₂

C. SCl₂

D. PoCl₃

Solution: (A)

When thionyl chloride SOCl₂ reacts with white phosphorus, phosphorus trichloride is produced.

P + 8SOCl₂ → 4PCl₃ + 4SO₂ + 2S₂Cl₂

Question 9. Concentrated nitric acid, upon long-standing, turns yellow-brown due to the formation of NO₂. State whether the given statement is true or false.

Solution: (True)

Concentrated nitric acid upon long-standing turns yellow-brown. This is due to the formation of brown coloured gas (NO₂) during the process.

4HNO₃ → 2H₂O + 4NO₂ + O₂

This gas basically imparts the colour to concentrated HNO₃ during long-standing.

Question 10. Bleaching powder contains a salt of an oxoacid as one of its components. The anhydride of that oxoacid is:

A. Cl₂O

B. Cl₂O₇

C. ClO₂

D. Cl₂O₆

Solution: (A)

Bleaching powder is Ca(OCl)Cl. Therefore, the oxoacid whose salt is present in bleaching powder is HOCl.

Anhydride of HOCl is Cl₂O as;

2HOCl → Cl₂O + H₂O

Note: The oxidation number of the element in anhydride and oxoacid remains the same.

Also Read:

p-Block Elements – Important Topics

p-Block Elements – Important Questions