Kinematics Formula is altogether about the motion of bodies at points, devoid of considering the cause because of which it happens. Kinematic formulas are three to be precise:
v=vo+at
v2=v2o+2a(x-xo)
At this juncture,
x and xo are Final and Initial displacements articulated in m,
vo and v are initial and final velocity articulated in m/s,
acceleration is a and articulated in m/s2,
the time taken is t in s.
Kinematics Formulas – 2D
2 dimensional or 2D kinematics equations is all about expressing the same equations in x and y directions:
In x direction the Kinematics formulas is articulated as:
vx = vxo + axt
x = xo + vxot + 1212 axt2
vx2 = vxo + 2ax(x-xo)
In y-direction the Kinematic formula is articulated as:
vy = vyo + ayt
y = xo + vyot + 1212 ayt2
vy2 = vyo2 + 2ay(y – yo)
Kinematics Formulas for Projectile Motion
Imagine a projectile motion as presented in the figure.Thus, the kinematics formulas are:
In x-direction:
vx = vxo
x = xo + vxo
In y-direction:
vy = vyo – gt
y = yo + vyot –1212 gt2
vy2 = vyo2 – 2g(y – yo)
Kinematic Equation Formulas
\(\begin{array}{l}v=v_{0}+at\end{array} \) |
\(\begin{array}{l}\Delta x=(\frac{v+v_{0}}{2})t\end{array} \) |
\(\begin{array}{l}\Delta x=v_{0}t+\frac{1}{2}at^{2}\end{array} \) |
\(\begin{array}{l}v^{2}=v_{0}^{2}+2a\Delta x\end{array} \) |
Kinematics Solved Example
Problem 1: A car with initial velocity zero experiences a uniform acceleration of 7 m/s2 for the time interval t= 5s. Calculate its distance covered?
Answer:
Given parameters
vo = 0
t = 5s
a = 7 m/s2
To find the Distance covered S.
By using the Kinematic Equation, one can determine that
S = 0 × 5 + (0.5 × 7 × 52)
S = 87.5 m
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