Kinematics Formulas

Kinematics Formula is altogether about the motion of bodies at points, devoid of considering the cause because of which it happens. Kinematic formulas are three to be precise:


At this juncture,

x and xo are Final and Initial displacements articulated in m,

vo and v are initial and final velocity articulated in m/s,

acceleration is a and articulated in m/s2,

the time taken is t in s.

Kinematics Formulas – 2D

2 dimensional or 2D kinematics equations is all about expressing the same equations in x and y directions:

In x direction the Kinematics formulas is articulated as:

vx = vxo + axt

x = xo + vxot + 1212 axt2

vx2 = vxo + 2ax(x-xo)

In y-direction the Kinematic formula is articulated as:

vy = vyo + ayt

y = xo + vyot + 1212 ayt2

vy2 = vyo2 + 2ay(y – yo)

Kinematics Formulas for Projectile Motion

Imagine a projectile motion as presented in the figure.Thus, the kinematics formulas are:

In x-direction:

vx = vxo

x = xo + vxo

In y-direction:

vy = vyo – gt

y = yo + vyot –1212 gt2

vy2 = vyo2 – 2g(y – yo)

Kinematic Equation Formulas

\(\begin{array}{l}v=v_{0}+at\end{array} \)
\(\begin{array}{l}\Delta x=(\frac{v+v_{0}}{2})t\end{array} \)
\(\begin{array}{l}\Delta x=v_{0}t+\frac{1}{2}at^{2}\end{array} \)
\(\begin{array}{l}v^{2}=v_{0}^{2}+2a\Delta x\end{array} \)

Kinematics Solved Example

Problem 1: A car with initial velocity zero experiences a uniform acceleration of 7 m/s2 for the time interval t= 5s. Calculate its distance covered?


Given parameters

vo = 0

t = 5s

a = 7 m/s2

To find the Distance covered S.

By using the Kinematic Equation, one can determine that

\(\begin{array}{l}S=v_{0}t+\frac{1}{2}at^{2}\end{array} \)


S = 0 × 5 + (0.5 × 7 × 52)

S = 87.5 m

Stay tuned with BYJU’S to learn more on Physics-related concepts.

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