Law of Sines Formula

To calculate the unknown sides and angles of a triangle, Law of Sines formula is used. The ratio of any side to the sine of the angle opposite to that side, should be the same for all the sides of the triangle. If two sides are given and two angles of the triangle are given, then the unknown angle can be knows using law of sines formula.

Law of sines formula

The Law of Sines Formula is,

\[\large \frac{a}{Sin\; A}=\frac{b}{Sin\; B}=\frac{c}{Sin\;C}\]

Solved Examples

Question 1: In a triangle ABC, the side lengths AB = 5 cm; BC = 3 cm and CA = 4 cm. The angle opposite to the side A is 60o. Calculate the other unknown angles ?

AB = a = 5 cm
BC = b = 3 cm
CA = c = 4 cm
A = 60oThe law of sines formula is,$\frac{a}{sin A}$ = $\frac{b}{sin B}$ = $\frac{c}{sin C}$$\frac{5 cm}{sin 60}$ = $\frac{3 cm}{sin B}$ = $\frac{4 cm}{sin C}$

$\frac{5 cm}{0.866}$ = $\frac{3 cm}{sin B}$ = $\frac{4 cm}{sin C}$

5.77 cm = $\frac{3 cm}{sin B}$ = $\frac{4 cm}{sin C}$

Solving 1st and 2nd term,

$\frac{3 cm}{sin B}$ = 5.77 cm

$\frac{3 cm}{5.77 cm}$ = $sin B$

$sin B$ = 0.52
B = 31.33o
Solving 2nd and 3rd term,

$\frac{4 cm}{sin C}$ = 5.77 cm

$\frac{4 cm}{5.77 cm}$ = $sin C$

$sin C$ = 0.69
C = 43.89o

Practise This Question

A body moves a distance of 10 m along a straight line under the action of a force of 5 N. If the work done is 25 joule, the angle which the force makes with the direction of motion of the body is