Important Questions Class 8 Maths Chapter 10 Visualising Solid Shapes

Some important questions for class 8 maths chapter 10 – Visualising Solid Shapes are provided here along with solutions. These questions are presented as per the CBSE guidelines and taking NCERT book as a reference by our experts. Based on the latest syllabus, the question papers will be prepared for the final exam. Hence, students should practice these problems to score well.

In this chapter, Visualising solid shapes, students will solve problems based on different solid shapes. To prepare for all the chapters, click here: Important Questions Class 8 Maths. These materials will help you to revise all the topics before appearing for the examination.

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Important Questions with Solutions for Class 8 Maths Chapter 10 (Visualising Solid Shapes)

1. How many faces, edges and vertices do a triangular prism and a triangular pyramid has?

Solution:

The number of faces, edges and vertices of a triangular prism is:

Shape Faces Edges Vertices
Triangular Prism 5 9 6
Triangular Pyramid 4 6 4

2. What is Euler’s formula for polyhedron?

Solution:

Euler’s formula for polyhedron states that for nay solid shape, number of vertices (V) minus the number of edges (E) plus the number of faces (F) always equals to 2.

So, V – E + F = 2

3. A tetrahedron has 4 vertices and 6 edges. Find the number of faces it has.

Solution:

Using Euler’s formula for polyhedra,

V – E + F = 2

So, 4 – 6 + F = 2

F = 2 + 2

F = 4.

4. What is the minimum number of planes that are required to form a solid?

Solution:

At least 4 planes are required to form a solid. The solid formed with only 4 planes is called a tetrahedron or a triangular pyramid.

5. Find the missing numbers: 

Faces Vertices Edges
6 8 ?
? 10 15
4 ? 6
5 6 ?
8 12 ?
7 7 ?

Solution:

Using the Euler’s formula for finding the missing numbers: V – E + F = 2

Faces Vertices Edges
6 8 12
7 10 15
4 4 6
5 6 9
8 12 18
7 7 12

Q.6: A polyhedron has 7 faces and 10 vertices. How many edges does the polyhedron have?

Solution: For any polyhedron,

F + V – E = 2

Given here, F = 7, V = 10, E = ?

Substituting the values, we get;

7 + 10 – E = 2

17 – E = 2

E = 17 – 2

E = 15

Q.7: The distance between City A and City B on a map is given as 6 cm. If the scale represents  1 cm = 200 km, then find the actual distance between the two cities.

Solution: Actual distance represented by 1 cm = 200 km

Actual distance represented between city A and B, by 6 cm = 6 x 200 km = 1200 km

So the actual distance between city A and city B is 1200 km.

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