A triangle is a closed two-dimensional figure with three sides. There are different ways to construct a triangle. If the three sides are given, we can easily construct a triangle. Similarly, construction of a triangle can be easily done when two sides – one included angle is given or two angles – one included side is given. In these cases, constructing a triangle is pretty easy. What if two angles and perimeter of a triangle is given? Is it possible to construct the triangle? And the answer is Yes. Thus, in this article, we are going to discuss how to construct a triangle when its perimeter and its two angles are given.

## How to Construct a Triangle When its perimeter and Two Angles are Given?

Below are the steps to construct a triangle ABC when its perimeter (i.e. AB + BC + CA) and two base angles B and C are given.

**Given: **The Perimeter (AB + BC + CA) of the triangle and two angles (i.e. âˆ B and âˆ C).

**Requirements: **A ruler, a protractor and a compass.

**Steps of Construction:**

Step 1: Draw a line segment XY such that XY = AB + BC + CA (i.e. perimeter of triangle ABC) and draw the angle lines at X and Y such that âˆ LXY = âˆ B and âˆ MYX = âˆ C.

Step 2: Draw the angle bisectors of âˆ LXY and âˆ MYX and let them meet at A.

Step 3: Now, draw the perpendicular bisectors of AX and AY such that they intersect XY at B and C respectively. Join AB and AC.

Hence, this is the required triangle ABC.

### Example

Go through the example given below for a better understanding of the above construction steps.

**Question:** Let us consider a triangle ABC, whose perimeter is 15 cm and the two given angles are 55Â° and 60Â°. That means AB +BC + CA = 15 cm , âˆ B = 55Â° andÂ âˆ C = 60Â°. Construct a triangle ABC with these measurements.

**Solution:**

Given,

AB + BC + CA = 15 cm (perimeter)

âˆ B = 55Â° andÂ âˆ C = 60Â°

The steps of construction are:

- Draw a line segment XY of length equal to AB + AC + BC, that is, 15 cm.
- From point X, using the protractor construct âˆ LXY which is equal to âˆ B, that is, 55Â°.
- From the point Y, construct âˆ MYX which is equal to âˆ C, that is, 60Â°.
- Using the compass, construct the bisectors of âˆ LXY and âˆ MYX. Mark the point as A where these bisectors meet.

- Construct the perpendicular bisector of AX and name it as PQ.
- Construct the perpendicular bisector of AY and name it as RS.
- Let PQ meet XY at B and RS meet XY at C.
- Join the points A and B as well as A and C.

Hence, âˆ†ABC is the required triangle with the given measurements.

Can this process be applicable?

Angle A= 65Â°

Ratio of angles= 13:11:12

So BC= 13x

AB= 12x

AC=11x

Perimeter=15cm= 13x+ 12x+ 11x

So x= 5/12

Hence, AB=5 cm

So the construction is done likewise.