Subtraction Questions

Subtraction questions with solutions are given here for students to practice and improve their skills. Subtraction is one of the arithmetic operations in mathematics: multiplication, division, subtraction and addition. This mathematical operation is introduced in elementary classes to teach kids how to subtract two or more numbers. Subtraction questions with solutions are given here for students to practice and improve their skills.

The minus sign ‘–’ is used to denote subtraction. We often use words like – “difference”, “take away”, “less than”, “deduct”, “minus”, “decrease”, “remaining”, etc., to express subtraction. For example, there are 10 oranges in a basket; if 6 oranges are taken away, how many oranges are left?

To find the answer, we have to subtract 6 from 10, that is, 10 – 6 = 4. In many of our daily life situations, we unknowingly use subtraction – while shopping, we use subtraction to pay the amount to the shopkeeper. Hence, it is essential for kids to practice subtraction questions thoroughly.

Learn more about subtraction.

Subtraction Questions with Solutions

Below are the questions based on subtraction operation for practice, along with solutions.

Question 1: Evaluate the following:

(i) 23 – 9

(ii) 89 – 67

(ii) 7 – 5

(iv) 65 – 34

Solution:

(i) 23 – 9 = 14 (Subtract by regrouping)

Refer: Addition and Subtraction

(ii) 89 – 67 = 22

(iii) 7 – 5 = 2

(iv) 65 – 34 = 31

Question 2: Subtract the following:

(i) 289 from 340

(ii) 196 from 762

(iii) 20 from 786

Solution:

(i) 289 from 340

340 – 289 = 51

(ii) 196 from 762

762 – 196 = 566

(iii) 20 from 786

786 – 20 = 766

Also, read:

• Addition and Subtraction of Integers
• Subtraction of Fractions
• Addition and Subtraction of Decimals
• Subtraction Calculator

Question 3: Evaluate the following:

(i) – 234 + 120

(ii) 90 – ( – 30)

(iii) 378 + ( – 38)

(iv) 1001 – 120 + 100

Solution:

(i) – 234 + 120 = –114

(ii) 90 – ( – 30) = 90 + 30 = 120

(iii) 378 + ( – 38) = 378 – 38 = 340

(iv) 1001 – 120 + 100 = (1001 + 100) – 120

= 1101 – 120 = 981

Question 4: Evaluate the following:

(i) 33/2 – 15/2

(ii) 4/3 – 5/3 + 8/3

(iii) 6/5 + 9/2 – 14/5

Solution:

(i) 33/2 – 15/2 = (33 – 15)/2 = 18/2 = 9

(ii) 4/3 – 5/3 + 8/3 = (4 – 5 + 8)/3 = {(4 + 8) – 5}/3

= {12 – 5}/3 = 7/3

(iii) 6/5 + 9/2 – 14/5 = (6/5 + 9/2) – 14/5

= [(6 × 2)/(5 × 2) + (9 × 5)/(2 × 5)] – 14/5

= [12/10 + 45/10] – 14/5

= 57/10 – 14/5

= 57/10 – (14 × 2)/(5 × 2)

= 57/10 – 28/10 = 29/10 = 2.9.

Question 5: Evaluate the following:

(i) Take away the sum of 120 and 38 from 250.

(ii) Twice the difference of 230 and 67.

(iii) x equals to 5 less than three times 32.

(iv) A deduction of ₹ 300 from the bill of ₹ 650.

Solution:

(i) Take away the sum of 120 and 38 from 250

250 – ( 120 + 38 ) = 250 – 158

= 92.

(ii) Twice the difference of 230 and 67

2 × ( 230 – 67 ) = 2 × 163 = 326.

(iii) x equals to 5 less than three times 32

(3 × 32) – 5 = x

Or, 96 – 5 = x

∴ x = 91.

(iv) A deduction of ₹ 300 from the bill of ₹ 650.

₹ 650 – ₹ 300 = ₹ 350.

Question 6: Fill in the blanks:

(i) 628 + ___ = 1000

(ii) 87 – ___ + 21 = 93

(iii) ___ – 100 = 283

(iv) 94 + ___ – 45 = 107

Solution:

(i) 628 + ___ = 1000

Now, 1000 – 628 = 372

∴ 628 + 372 = 1000.

(ii) 87 – ___ + 21 = 93

93 – 21 = 72

Then, 87 – ___ = 72

Now, 87 – 72 = 15

∴ 87 – 15 + 21 = 93.

(iii) ___ – 100 = 283

283 + 100 = 383

∴ 383 – 100 = 283.

(iv) 94 + ___ – 45 = 107

107 + 45 = 152

So, 94 + ___ = 152

152 – 94 = 58

∴ 94 + 58 – 45 = 107.

Question 7: Find the missing digits:

(i) 2__65 – __5 = __770

(ii) 8__8 – __2__ = 757

(iii) 1__9__ – 7__5 = 573

Solution:

(i) 2865 – 95 = 2770

(ii) 878 – 121 = 757

(iii) 1298 – 725 = 573

Question 8: Find the value of A, B and C:

12215 – 3BA1 = A65C

Solution:

Now starting from ones column, 5 – 1 = C

⇒ C = 4

In tens column, 1 – A = 5, as 5 > 1, therefore 1 is made 11 by regrouping from the hundreds column.

11 – A = 5

⇒ A = 6

In hundreds column, 1 – B = 6 (as we exchanged 1 into the tens column), again 6 > 1, therefore 1 is made 11 by regrouping from the thousands column

11 – B = 6

⇒ B = 5

Thus, we have 12215 – 3561 = 8654.

Question 9: Monthly salary of Rita is ₹ 30,000. In June she spent ₹ 20,000 and in July she spent ₹ 15,000. How much she saved in these two months?

Solution:

Monthly salary = ₹ 30,000

Expenditure in June = ₹ 20,000

Expenditure in July = ₹ 15,000

Total expenditure = ₹ (20,000 + 15,000) = ₹ 35,000

Total salary = 2 × 30,000 = ₹ 60,000

Total savings = ₹ (60,000 – 35,000) = ₹ 25,000.

Question 10: A tank contains 500 litres of water. There is a small hole in the tank through which the water is leaking. If per hour 1-litre water leaks. How much water is left inside the tank after 5 hours?

Solution:

Amount of water inside the tank = 500 litres

Loss of water in 1 hour = 1 litre

Loss of water in 5 hours = 5 × 1 litre = 5 litres

Water left inside the tank after 5 hours = 500 – 5 = 495 litres of water.

Question 11: A shopkeeper buys a washing machine for ₹ 20,000, then he sells that washing machine for ₹ 25,000. How much profit did the shopkeeper made?

Solution:

Cost price of washing machine = ₹ 20,000

Selling price of washing machine = ₹ 25,000

Profit = ₹ 25,000 – ₹ 20,000 = ₹ 5000

Therefore, the shopkeeper made a profit of ₹ 5000.

Question 12: Find the number which is, when subtracted from 2980, results in the smallest 4-digit number.

Solution:

Smallest 4-digit number = 1000

Now, 2980 – ____ = 1000

Then, 2980 – 1000 = 1980

Therefore, 1980 must be subtracted from 2980 to get 1000.

Practice Questions

1. Evaluate the following:

(i) 97 – 45

(ii) 956 – 178

(iii) 482 – 95

2. Evaluate the following:

(i) 87.78 – 45.2

(ii) 78.34 – 0.45

(iii) 3765 – 234.90

3. In an examination, 2 mark is rewarded for a correct answer, and 1 mark is deducted for a wrong answer. Rahul attempted 50 questions, out of which there were 10 wrong answers. How much did he score in the examination?

4. To stitch a shirt 3 m of cloth is required. A tailor made 20 shirts out of a cloth of 100 m. How much cloth is left?